Javascript 匹配两个数组数据并得到其总和！（算法…？）

我想匹配时间和日期 结果应该是每个日期的时间总和。。。 例如…06/27-应该是30和90的和…依此类推。 我该怎么做

var array_date=["2017/06/27","2017/06/26","2017/06/27","2017/06/26","2017/06/28"]

var array_time=["30","50","90","120","20"]

var obj = array_date;
for (var i = 0 in obj) {
  console.log("rr:"+obj[i]);
}

//To filter date I used below method...anyway. 
var cleanArray = displayed_date.filter((value,index,self)=>{ return (self.indexOf(value) === index )});

---

首先，由于您正在进行加法，因此最好将字符串转换为数字：

array_time = array_time.map(t=> +t);

接下来，按日期对时间进行分组和求和：

let data = array_date.reduce((acc, d, i)=> {
    if(acc.hasOwnProperty(d)) acc[d] += array_time[i];
    else acc[d] = array_time[i];
    return acc;
}, {});

---

您可以这样做：

       <script>
        array_date=["2017/06/27","2017/06/26","2017/06/27","2017/06/26","2017/06/28"];

        array_time=["30","50","90","120","20"];

        var oData = [];

        for(var i = 0; i < array_date.length; i++ ){

            if(Object.keys(oData).length > 0){
              var icount = 0;
              for(var x = 0; x < Object.keys(oData).length; x++){

                if(oData[x]['date'] == array_date[i]){
                  oData[x]['sum'] = parseInt(oData[x]['sum']) + parseInt(array_time[i]);
                  icount++;
                }
              }

              if(icount == 0){
                var oCreate = {"date":array_date[i], "sum":parseInt(array_time[i])}

                  oData.push(oCreate);
              }

            }else{
              var oCreate = {"date":array_date[i], "sum":parseInt(array_time[i])}

              oData.push(oCreate);
            }

        }

        console.log(JSON.stringify(oData)); //oData is the final variable answer here.

   </script>

数组_日期=[“2017/06/27”、“2017/06/26”、“2017/06/27”、“2017/06/26”、“2017/06/28”]；
数组_时间=[“30”、“50”、“90”、“120”、“20”]；
var oData=[]；
对于（变量i=0；i0）{
var-icount=0；
for（var x=0；x

希望这会有帮助