香草JavaScript:按数组过滤嵌套数组
考虑以下一系列帖子:香草JavaScript:按数组过滤嵌套数组,javascript,arrays,multidimensional-array,Javascript,Arrays,Multidimensional Array,考虑以下一系列帖子: posts_array = [ { id: 1, categories: [ { category_id: 1, category_name: "one" }, { category_id: 2, category_name: "two" }, }, { id: 2, categories: [ { category_id: 1, category_name: "one"
posts_array =
[
{
id: 1,
categories: [
{
category_id: 1,
category_name: "one"
},
{
category_id: 2,
category_name: "two"
},
},
{
id: 2,
categories: [
{
category_id: 1,
category_name: "one"
},
{
category_id: 3,
category_name: "three"
},
},
{
id: 3,
categories: [
{
category_id: 1,
category_name: "one"
},
{
category_id: 4,
category_name: "four"
},
{
category_id: 5,
category_name: "five"
},
}
]
然后我有一个类别ID数组,我想用它来过滤上面的数组:
const category_id_array = [1, 4];
我希望进行筛选以满足所有条件,即返回posts\u数组中的元素,这些元素包括两个类别。类别\u id=1和类别。类别\u id=4
function filterPostsByCategoryIds(category_id_array){
const filter_categories = category_id_array;
const custom_filter = d => d.categories.some(c => filter_categories.includes(c.category_id));
const filtered_posts_array = posts_array.filter(custom_filter);
return filtered_posts_array;
}
我尝试了下面的方法(使用.some函数),但它返回满足任一条件的元素,即categories.category\u id=1或categories.category\u id=4
function filterPostsByCategoryIds(category_id_array){
const filter_categories = category_id_array;
const custom_filter = d => d.categories.some(c => filter_categories.includes(c.category_id));
const filtered_posts_array = posts_array.filter(custom_filter);
return filtered_posts_array;
}
交换.some with.each完全不返回任何元素
如何按类别\u id\u数组过滤posts\u数组,使其返回上述示例数组中的最后一个元素,即类别包含类别\u id\u数组中的所有类别\u id
谢谢,注意安全 您可以在类别id\u数组中使用.every()
,当中存在时,返回true
。当前类别中的某些()
对象的类别id
与类别id\u数组中的当前id(c
)相等:
const posts_数组=[{id:1,类别:[{category_id:1,category_name:“one”},{category_id:2,category_name:“two”},},{id:2,category:[{category_id:1,category_name:“one”},{categegegegegegegory_id:3,categories:[{categority_id:1,categority_name:“one”},{categority_id:4,categority_name:“四”},{category_id:5,category_name:“五”},}];
函数filterPostsByCategoryId(类别id数组){
const custom_filter=d=>category_id_array.every(c=>d.categories.some(o=>o.category_id==c));
const filtered\u posts\u array=posts\u array.filter(自定义\u过滤器);
返回过滤后的\u posts\u数组;
}
const res=filterPostsByCategoryId([1,4]);
console.log(res);