Javascript 如何划分一组数字，使其始终在0到100之间？

我有一组数字，它们的最大值可以是千，我希望它在0到100之间。以便在实际中使用它

控制台输出

 Event "stabilized" triggered
 Object {iterations: 0}
 Event "stabilizationProgress" triggered
 Object {iterations: 50, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 100, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 150, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 200, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 250, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: , total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: , total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 400, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 450, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 500, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 550, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 600, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 650, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 700, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 750, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 800, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 850, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 900, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 950, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1000, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1050, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1100, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1150, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1200, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1250, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1400, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1450, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1500, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1550, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1600, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1650, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1700, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1750, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1800, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1850, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1900, total: 2000}
 Event "stabilizationProgress" triggered
 Object {iterations: 1950, total: 2000}
 Event "stabilizationIterationsDone" triggered
 Event "stabilized" triggered
 Object {iterations: 2001}

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在数学上，将每个数字除以最大值，然后乘以100。

在数学上，解决方案似乎很简单：取数值的百分比，你的计算几乎是正确的，只需添加两个参数：

Math.round((arguments[0].iterations / arguments[0].total)*100);

因此，假设你有这样的情况：

Event "stabilizationProgress" triggered
 Object {iterations: 900, total: 2000}

计算值应为：

Math.round((arguments[0].iterations / arguments[0].total)*100);
Math.round((900 / 2000)*100);
Math.round((9 / 20)*100);
Math.round((0.45)*100);
=45

您最初的计算结果是：

Math.round(arguments[0].iterations / arguments[0].total)*100;
Math.round(900 / 2000)*100
Math.round(0.45)*100

原因：
1） Math.round（）方法将为Math.round（0.45）{即值<0.5但大于0}，这就是为什么得到：0*100=0。

2） 对于像Math.round（0.75）{value>0.5但<1}这样的值，这个方法将返回1，这就是为什么得到：1*100=100

本质上，你的公式只会给你两个值0或100。有道理吗

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参考：

谢谢我让它运行

Math.round（（参数[0]。迭代次数/参数[0]。总计）*100）

。对于其他人，Kailas回答中解释了解决方案谢谢，但Wheeldog的回答帮助我首先解决了问题，正如您在解决方案中解释的那样。

Math.round(arguments[0].iterations / arguments[0].total)*100;
Math.round(900 / 2000)*100
Math.round(0.45)*100