Javascript AmChart未显示第二个y轴
我被分配了在一个图形中显示两个图表的任务,因此我需要两个y轴来表示图表。 一个轴位于左侧,另一个轴位于右侧 我的问题是只显示一个y轴。 在使用amCharts时,我注意到一个问题,即可见y轴有一个名为allLabels的数组,其中包含元素,但第二个y轴没有,但我不知道 填充该数组属性的内容 代码: 图表现在的样子:Javascript AmChart未显示第二个y轴,javascript,amcharts,Javascript,Amcharts,我被分配了在一个图形中显示两个图表的任务,因此我需要两个y轴来表示图表。 一个轴位于左侧,另一个轴位于右侧 我的问题是只显示一个y轴。 在使用amCharts时,我注意到一个问题,即可见y轴有一个名为allLabels的数组,其中包含元素,但第二个y轴没有,但我不知道 填充该数组属性的内容 代码: 图表现在的样子: 图形没有属性valueAxis,请改用valueAxis: 图2.valueAxis=yAxis2 图形没有属性valueAxis,请改用valueAxis: 图2.valueAxi
图形没有属性valueAxis,请改用valueAxis:
图2.valueAxis=yAxis2 图形没有属性valueAxis,请改用valueAxis: 图2.valueAxis=yAxis2
function addconsumerUsageGraph(consumerUsageGraph) {
//You can ignore this
if (consumerUsageGraph.graphs.length == 2)
{
var gr1 = consumerUsageGraph.graphs[0];
var gr2 = consumerUsageGraph.graphs[1];
consumerUsageGraph.removeGraph(gr1);
consumerUsageGraph.removeGraph(gr2);
}
if (consumerUsageGraph.graphs.length == 1) {
var gr1 = consumerUsageGraph.graphs[0];
consumerUsageGraph.removeGraph(gr1);
}
//I add the two yAxis here:
var yAxis1 = new AmCharts.ValueAxis();
yAxis1.position = "left";
var yAxis2 = new AmCharts.ValueAxis();
yAxis2.position = "right"; // set this to "right" if you want it on the right
//Adding the value axis to the whole graph
consumerUsageGraph.addValueAxis(yAxis1);
consumerUsageGraph.addValueAxis(yAxis2);
var graph = new AmCharts.AmGraph();
graph.valueField = "value";
graph.type = "column";
graph.title = "Usage";
graph.lineAlpha = 1;
graph.fillAlphas = 0.75;
consumerUsageGraph.addGraph(graph);
var graph2 = new AmCharts.AmGraph();
graph2.valueField = "cost";
graph2.type = "line";
graph2.lineAlpha = 1;
graph2.title = "Cost";
graph2.lineColor = graphColour;
graph2.bullet = "round";
graph2.bulletAlpha = 0.5;
graph2.bulletBorderAlpha = 0.8;
//Assigning the second yAxis to the second graph
graph2.valueAxes = yAxis2;
consumerUsageGraph.addGraph(graph2);
//consumerUsageGraph.write("chartdiv");
var legend = new AmCharts.AmLegend();
legend.marginBottom = -10;
legend.useGraphSettings = true;
consumerUsageGraph.addLegend(legend);
}