Javascript:浮点值未正确显示

我有一个从谷歌金融获取数据的代码。然而，如果存在代表数百万和数千的M或K，它可以正确地获得vo和avvo的数据。如果没有它，则无法正确显示值

如何处理这两种情况以正确获取数据

示例数据如下所示。第一个有浮点数据，第二个有M，我认为是字符串。我可以正确显示字符串，但浮点不正确。它将vo显示为N/A，avvo显示为2.000。我想显示数据中的精确值

// [
{
"id": "549805688244420"
,"t" : "AZG"
,"vo" : "0.00"
,"avvo" : "2,087.00"

}
]

及

下面是我的代码：

angular.module('myapp.factories').factory('$stockDataFactory',
  ['$q', '$filter', '$webServicesFactory',
    function ($q, $filter, $webServicesFactory) {
      return {
        getStockDetails: function (stock) {
          var deferred = $q.defer();

          $webServicesFactory.getNotParsed(
            "https://www.google.com/finance/info",
            {},
            {
              infotype: "infoquoteall",
              q: stock.market+":"+stock.symbol
            }
          ).then(
            function success(response) {
              response = JSON.parse("["+response.replace(/\r?\n|\r/g, ' ').split('[').splice(1,1)[0]);
              stock = response[0];
        var formatedData = {
                  volume: stock.vo,
                  averageDailyVolume: stock.avvo
           };

html:

卷：
{{stock.volume | |'N/A'}
平均体积：
{{（stock.averageDailyVolume |收缩数：2）| | N/A'}

js中的收缩数

angular.module('chaishen.factories').filter("shrinkNumber", function($filter) {
  return function(number, fractionSize) {

    if(number === null) return null;
    if(number === 0) return "0.000";

    // default number of decimals for values >1000 or <-1000 if not set in view
    if(!fractionSize || fractionSize < 0)
      fractionSize = 1;

    var abs = Math.abs(number);
    var rounder = Math.pow(10,fractionSize);
    var isNegative = number < 0;
    var key = '';
    var powers = [
      {key: "Q", value: Math.pow(10,15)},
      {key: "T", value: Math.pow(10,12)},
      {key: "B", value: Math.pow(10,9)},
      {key: "M", value: Math.pow(10,6)},
      {key: "K", value: 1000}
    ];

    for(var i = 0; i < powers.length; i++) {

      var reduced = abs / powers[i].value;

      //reduced = Math.round(reduced * rounder) / rounder;
      reduced = Math.round(abs * rounder) / rounder;

      if(reduced >= 1){
        abs = reduced;
        key = powers[i].key;
        break;
      }
    }

    if(number >= 1000) {
      //return abs + key;
      return abs;
    }
    else if(number <= -1000) {
      //return '-' + abs + key;
      return '-' + abs;
    }
    else {
      //return $filter('number')(((isNegative ? '-' : '') + abs + key), 3);
      return $filter('number')(((isNegative ? '-' : '') + abs), 3);
    }
  };
});

angular.module（'chaishen.factories'）.filter（'shrinkNumber'，函数（$filter）{
返回函数（数字、分形大小）{
if（number==null）返回null；
如果（数字===0）返回“0.000”；
//值>1000或=1时的默认小数位数）{
abs=减少的；
key=powers[i].key；
打破
}
}
如果（数字>=1000）{
//返回abs+键；
返回abs；
}
否则，如果（number@OneNeptune）与我的问题有什么关系？声明为它们，则您的浮点值只是字符串。但“浮点值不正确”是什么意思？它们是如何显示的？你正确的方式是什么？它在html页面上吗？在哪里？@Kaddath edit添加了html。它显示0为N/a，2870.00为2.00。我在html中输入N/a，就像有时一样，数据是“-”，它将显示为N/a。Thanks@bkcollection你仍然在尝试对字符串进行数学运算。这对你来说是行不通的有三种不同的强制方式：
Number（stock.avvo）；+stock.avvo；parseInt（stock.avvo，10）
。
  <div class="row row-center">
    <div class="col boldText">Volume: </div>
    <div class="col col-21">{{stock.volume || 'N/A'}}</div>
    <div class="col boldText">Avg. Vol: </div>
    <div class="col col-21">{{(stock.averageDailyVolume | shrinkNumber: 2) || 'N/A'}}</div>
  </div>

angular.module('chaishen.factories').filter("shrinkNumber", function($filter) {
  return function(number, fractionSize) {

    if(number === null) return null;
    if(number === 0) return "0.000";

    // default number of decimals for values >1000 or <-1000 if not set in view
    if(!fractionSize || fractionSize < 0)
      fractionSize = 1;

    var abs = Math.abs(number);
    var rounder = Math.pow(10,fractionSize);
    var isNegative = number < 0;
    var key = '';
    var powers = [
      {key: "Q", value: Math.pow(10,15)},
      {key: "T", value: Math.pow(10,12)},
      {key: "B", value: Math.pow(10,9)},
      {key: "M", value: Math.pow(10,6)},
      {key: "K", value: 1000}
    ];

    for(var i = 0; i < powers.length; i++) {

      var reduced = abs / powers[i].value;

      //reduced = Math.round(reduced * rounder) / rounder;
      reduced = Math.round(abs * rounder) / rounder;

      if(reduced >= 1){
        abs = reduced;
        key = powers[i].key;
        break;
      }
    }

    if(number >= 1000) {
      //return abs + key;
      return abs;
    }
    else if(number <= -1000) {
      //return '-' + abs + key;
      return '-' + abs;
    }
    else {
      //return $filter('number')(((isNegative ? '-' : '') + abs + key), 3);
      return $filter('number')(((isNegative ? '-' : '') + abs), 3);
    }
  };
});