Javascript 如何在typescript中将字符串转换为对象

我正在用Angular 6制作动态表格。为此，我从后端发送JSON。PFB json

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我正在用打字稿制作以下表格。PFB代码

this.dataList = JSON.parse(event.body); //Contains the JSON sent from backend
const formContent: any = {};

this.dataList.forEach(data => { 
      formContent[data.key] = new FormControl(data.value ,data.syncValidators));
 });

this.exampleForm = new FormGroup(formContent);

我在=>data.syncValidators中遇到了问题，因为它被视为字符串。但它需要验证器

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如何进行转换以使“data.syncValidators”被视为一种方法而不是字符串？

创建一个工厂以实现：

validatorFactory(validatorName:string){
     switch(validatorName){
          case "Validators.required" :
               return Validators.required;
          // add other validators like max , min , ....
          default : return null;
     }
}

然后像这样使用它：

    this.dataList.forEach(data => { 
      formContent[data.key] = new FormControl(data.value ,validatorFactory(data.syncValidators)));
    });

你可以用三元

        this.dataList.forEach(data => { 
              formContent[data.key] = (data.syncValidators == "Validators.required" ? 
                  new FormControl(data.value ,Validators.required)) : new FormControl(data.value)));
        });

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这就是答案@Harshit。但是可以有一组验证程序，比如新的FormControl（data.value、Validators.required、Validators.email）；

        this.dataList.forEach(data => { 
              formContent[data.key] = (data.syncValidators == "Validators.required" ? 
                  new FormControl(data.value ,Validators.required)) : new FormControl(data.value)));
        });