Javascript $.ajax成功回调未在firefox中启动
我遇到了一个问题,对$.ajax的调用成功完成并返回内容,firebug报告响应为200OK,但未执行成功、完成和错误回调。这只发生在firefox中,在chrome中工作正常,我正在运行firefox22Javascript $.ajax成功回调未在firefox中启动,javascript,jquery,ajax,firefox,cross-browser,Javascript,Jquery,Ajax,Firefox,Cross Browser,我遇到了一个问题,对$.ajax的调用成功完成并返回内容,firebug报告响应为200OK,但未执行成功、完成和错误回调。这只发生在firefox中,在chrome中工作正常,我正在运行firefox22 $.ajax(site_url+url+'/fetch_salt',{type:'POST',data:data,success:check_salt}); var group = ''; function check_salt(d) { console.log(d); fire
$.ajax(site_url+url+'/fetch_salt',{type:'POST',data:data,success:check_salt});
var group = '';
function check_salt(d)
{
console.log(d);
firebug报告的请求的实际响应为:
choose_login:{"admin":"Admin Zone"}
和响应类型:
Content-Type text/html
我曾尝试过在jquery假设json或其他情况下强制设置dataType和contentType,并尝试过匿名函数来处理错误、成功和完全回调,但没有任何效果
我正在发布完整的函数代码,以防出现某种语法错误:
function prep_login_form(elem,url,challenge)
{
function show_error(msg)
{
$(elem).find('.ecms-error-for-password .ecms-error-text').html(msg).closest('.ecms-error-container').removeClass('ecms-error-hidden');
}
function submit()
{
var data = {email:$(elem).find('input[name="email"]').val()};
data[csfr_token_name] = csfr_hash;
$.ajax({type:'POST',url:site_url+url+'/attempt_login',data:data,success:check_salt});
var group = '';
function check_salt(d)
{
console.log(d);
if (d=='no_email')
{
show_error('Invalid Email address');
}
else if (d=='account_disabled')
{
show_error('This account has been disabled, please contact your administrator');
}
else if (d.substr(0,12)=='choose_login')
{
var cl;
eval('cl = '+d.substr(13));
var cou = 0;
for (p in cl)
{
cou++;
}
if (cou==1)
{
group = p;
var mydata = $.extend(data,{group:p});
$.ajax(site_url+url+'/fetch_salt',{type:'POST',data:mydata,success:check_salt})
}
else
{
var str = '<div class="login-selection-popup"><p>We have detected that your email address is linked to more than one account.<br />Please select which zone you would like to login to.</p><ul class="choose-login-popup">';
for (p in cl)
{
str+='<li><a rel="'+p+'">'+cl[p]+'</a></li>';
}
str+='</ul></div>';
open_modal({heading:'Choose Account',content:str,buttons:function(close_modal)
{
$(this).find('.choose-login-popup').on('click','a',function()
{
group = $(this).attr('rel');
var mydata = $.extend(data,{group:$(this).attr('rel')});
$.ajax(site_url+url+'/fetch_salt',{type:'POST',data:mydata,success:check_salt})
close_modal();
});
}});
}
}
else
{
var salt = d;
var pw = $(elem).find('input[name="password"]').val();
data.password = hex_md5(challenge+hex_md5(salt+pw));
data.group = group;
$.ajax(site_url+url+'/attempt_login',{type:'POST',data:data,success:function(d)
{
if (d=='no_email')
{
show_error('Invalid username or password');//Invalid Email address
}
else if (d=='account_disabled')
{
show_error('This account has been disabled, please contact your administrator');
}
else if (d=='invalid_login')
{
show_error('Invalid username or password');//Email or Password did not match
}
else
{
window.location.href = d;
}
}});
}
}
}
$(elem).on('keyup','input',function(e)
{
if (e.keyCode=='13')
{
submit();
}
});
$(elem).find('.login-submit').on('click',function()
{
submit();
});
}
对不起,最近我在电脑上安装了一些插件,我很想摆脱它。我认为它破坏/劫持了我的firefox。重新安装firefox后,问题消失,回调现在执行。您是否尝试设置错误回调?可能您还没有注意到某个错误。我已经尝试了匿名函数来处理该错误,错误回调至少应该已经触发,即使它并不总是提供有用的信息。请尝试以下方法:$.ajax{type:'POST',url:site\u url+url+'/fetch\u salt',data:data,success:check\u salt};您好,就像我说的,我尝试过为error函数设置一个回调,它不会启动,而且它在任何情况下都会在chrome中执行成功回调。您是否尝试过在浏览器调试工具或Fiddler中监视网络流量以查看发生了什么?