Javascript 循环函数的返回值

此Meteor服务器递归方法

commonHint

将

result

未定义返回控制台，即使

finalRes

有值。
关于如何将

finalRes

返回给调用者有什么建议吗？thx

  //call the recursive method
  let result = this.commonHint(myCollection.findOne({age: 44}), shortMatches);
        console.log('got most common hint: ' + result); // <=== undefined ====

  'commonHint': function (doc, shortMatches, hinters, results = []) {
      // first call only first 2 args are defined,
      if (!hinters) {
        hinters = [...lib.getCombinations(['arg1', 'arg2', 'arg3'], 2, 3)];
        this.commonHint(doc, shortMatches, hinters, results);  // hinters is an array of length 3 with 2 elements each
        return;
      }

      // get an element from hinters, use its 2 hinters and remove that element from the hinters
      let hintersToUse = hinters.pop();
      let hinter1 = this.cleanMatchItem(hintersToUse[0]);
      let hinter2 = this.cleanMatchItem(hintersToUse[1]);
      let intersect = _.intersection(hinter1, hinter2);

      // which item of the shortMatches best matches with the intersect
      let tempCol = new Meteor.Collection();
      for (let i = 0; i < shortMatches.length; i++) { tempCol.insert({match: shortMatches[i]}); }
      results.push(mostSimilarString(tempCol.find({}), 'match', intersect.join(' ')));

      if (hinters.length > 0) {
        this.commonHint(doc, shortMatches, hinters, results);
      } else {
        let finalRes = lib.mostCommon(results);
        console.log(finalRes);  //<==== has a value
        return finalRes;        //<==== so return it to caller
      }
    },

//调用递归方法
让result=this.commonHint（myCollection.findOne（{age:44}），shortMatches）；
console.log（'得到最常见的提示：'+结果）；//0) {
这个.commonHint（文档、短匹配、提示、结果）；
}否则{
让finalRes=lib.mostCommon（结果）；
console.log（finalRes）；//您调用的任何地方
commonHint
您都需要返回调用的值

  ... 

  if (!hinters) {
    hinters = [...lib.getCombinations(['arg1', 'arg2', 'arg3'], 2, 3)];
    return this.commonHint(doc, shortMatches, hinters, results);  // hinters is an array of length 3 with 2 elements each
  }

  ...

  if (hinters.length > 0) {
    return this.commonHint(doc, shortMatches, hinters, results);

您调用的任何位置
commonHint
都需要返回调用的值

  ... 

  if (!hinters) {
    hinters = [...lib.getCombinations(['arg1', 'arg2', 'arg3'], 2, 3)];
    return this.commonHint(doc, shortMatches, hinters, results);  // hinters is an array of length 3 with 2 elements each
  }

  ...

  if (hinters.length > 0) {
    return this.commonHint(doc, shortMatches, hinters, results);

返回结果的递归函数中的每个路径都必须返回结果。在您的递归函数中，有不返回结果的路径：当未提供
hinters
时，以及当
hinters.length>0
为真时

您应该返回递归调用的结果：

  if (!hinters) {
    hinters = [...lib.getCombinations(['arg1', 'arg2', 'arg3'], 2, 3)];
    return this.commonHint(doc, shortMatches, hinters, results);  // hinters is an array of length 3 with 2 elements each
//  ^^^^^^
  }

  // ...

  if (hinters.length > 0) {
    return this.commonHint(doc, shortMatches, hinters, results);
//  ^^^^^^
  } else {
    let finalRes = lib.mostCommon(results);
    console.log(finalRes);  //<==== has a value
    return finalRes;        //<==== so return it to caller
  }

if（！提示）{
hinters=[…lib.getCombinations（['arg1'，'arg2'，'arg3']，2,3）]；
返回此.commonHint（doc、shortMatches、hinters、results）；//hinters是一个长度为3的数组，每个数组有2个元素
//  ^^^^^^
}
// ...
如果（hinters.length>0）{
返回此.commonHint（文档、短匹配、提示、结果）；
//  ^^^^^^
}否则{
让finalRes=lib.mostCommon（结果）；
console.log（finalRes）；//递归函数中返回结果的每个路径都必须返回结果。在您的函数中，有不返回结果的路径：当未提供
hinters
时，以及当
hinters.length>0
为true时

您应该返回递归调用的结果：

  if (!hinters) {
    hinters = [...lib.getCombinations(['arg1', 'arg2', 'arg3'], 2, 3)];
    return this.commonHint(doc, shortMatches, hinters, results);  // hinters is an array of length 3 with 2 elements each
//  ^^^^^^
  }

  // ...

  if (hinters.length > 0) {
    return this.commonHint(doc, shortMatches, hinters, results);
//  ^^^^^^
  } else {
    let finalRes = lib.mostCommon(results);
    console.log(finalRes);  //<==== has a value
    return finalRes;        //<==== so return it to caller
  }

if（！提示）{
hinters=[…lib.getCombinations（['arg1'，'arg2'，'arg3']，2,3）]；
返回此.commonHint（doc、shortMatches、hinters、results）；//hinters是一个长度为3的数组，每个数组有2个元素
//  ^^^^^^
}
// ...
如果（hinters.length>0）{
返回此.commonHint（文档、短匹配、提示、结果）；
//  ^^^^^^
}否则{
让finalRes=lib.mostCommon（结果）；
控制台日志（最终）//