如何使用Ajax将数组值从Javascript格式化为Javaservlet

如何使用Ajax将数组值从Javascript格式化为Javaservlet,javascript,java,json,ajax,servlets,Javascript,Java,Json,Ajax,Servlets,我需要你的帮助 我使用AJAX将这个数组从Javascript传递到Javaservlet Javascript和AJAX代码片段: var BuildingNo = []; $(xml).find('BUILDING').each(function(){ BuildingNo.push($.trim(this).children('BuildingNo').text()); } 传递到Javaservlet之前BuildingNo的值 alert(BuildingNo); // 0

我需要你的帮助

我使用AJAX将这个数组从Javascript传递到Javaservlet

Javascript和AJAX代码片段:

var BuildingNo = [];

$(xml).find('BUILDING').each(function(){
    BuildingNo.push($.trim(this).children('BuildingNo').text());
}
传递到Javaservlet之前BuildingNo的值

alert(BuildingNo);
// 00101,00102,00103,00104,00105 
data: { BuildingNo : JSON.stringify(BuildingNo) },

alert(JSON.stringify(BuildingNo));
// ["00101","00102","00103","00104","00105"] 
当我通过Ajax将BuildingNo传递给Javaservlet时,JSON.stringify(BuildingNo)的值

alert(BuildingNo);
// 00101,00102,00103,00104,00105 
data: { BuildingNo : JSON.stringify(BuildingNo) },

alert(JSON.stringify(BuildingNo));
// ["00101","00102","00103","00104","00105"] 
下面是我用来将BuildingNo传递给oldBuilding列表的Javaservlet代码片段

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws (ServletException, IOException {

List <String> oldBuildingList = Arrays.asList(request.getParameter("BuildingNo");

logger.info(oldBuildingList);

// [["00101","00102","00103","00104","00105"]] -- This is a wrong format.

//I have a Java code here which captures a new list of BuildingNo from another service.

List <String> newBuildingList = new ArrayList <String>();
logger.info(newBuildingList.toString());

// [00106,00107,00108,00109,00110] -- This should be the correct format of oldBuildingList.

}
受保护的void doGet(HttpServletRequest请求,HttpServletResponse响应)抛出(ServletException,IOException{
List oldBuildingList=Arrays.asList(request.getParameter(“BuildingNo”);
logger.info(旧构建列表);
//[[“00101”、“00102”、“00103”、“00104”、“00105”]——格式错误。
//我这里有一个Java代码,它从另一个服务捕获了BuildingNo的新列表。
List newBuildingList=newarraylist();
logger.info(newBuildingList.toString());
//[001060010700108010900110]——这应该是oldBuildingList的正确格式。
}

如何使用oldBuildingList获得相同格式的newBuildingList?

不要字符串化,只保留为
数据:{BuildingNo:BuildingNo}


在JavaServlet
List oldBuildingList=Arrays.asList(request.getParameterValues(“BuildingNo[]);

欢迎您的加入。很高兴听到@Ragome干杯!!