Javascript 按键合并JSON数据
我正在尝试合并几个关于天气数据的JSON文件,并试图找出最好的方法。我还发现了其他几个帖子,它们只是连接了JSON对象,或者在使用相同的键时第二个对象覆盖了第一个对象,等等,但是没有任何东西通过键合并它们 下面是我正在使用的示例和我想要的输出。任何关于这方面的建议都会很好 示例JSON0.jsonJavascript 按键合并JSON数据,javascript,json,merge,Javascript,Json,Merge,我正在尝试合并几个关于天气数据的JSON文件,并试图找出最好的方法。我还发现了其他几个帖子,它们只是连接了JSON对象,或者在使用相同的键时第二个对象覆盖了第一个对象,等等,但是没有任何东西通过键合并它们 下面是我正在使用的示例和我想要的输出。任何关于这方面的建议都会很好 示例JSON0.json { "1948": [ { "Seattle": { "city": "Seattle",
{
"1948": [
{
"Seattle": {
"city": "Seattle",
"data": {
"avg_dew_point": "34",
"avg_gust_wind": "",
"avg_max_temp": "45",
"avg_min_temp": "35",
"avg_precipitation": "0.00",
"avg_sea_level_pressure": "30.22",
"avg_temp": "40",
"avg_wind": "8"
},
"month": "1",
"state": "WA"
}
},
{
"Chicago": {
"city": "Chicago",
"data": {
"avg_dew_point": "10",
"avg_gust_wind": "",
"avg_max_temp": "25",
"avg_min_temp": "11",
"avg_precipitation": "0.00",
"avg_sea_level_pressure": "30.17",
"avg_temp": "18",
"avg_wind": "12"
},
"month": "1",
"state": "IL"
}
}
],
"1949": [
{
"Houston": {
"city": "Houston",
"data": {
"avg_dew_point": "45",
"avg_gust_wind": "",
"avg_max_temp": "61",
"avg_min_temp": "44",
"avg_precipitation": "0.00",
"avg_sea_level_pressure": "30.15",
"avg_temp": "53",
"avg_wind": "12"
},
"month": "1",
"state": "TX"
}
},
{
"Seattle": {
"city": "Seattle",
"data": {
"avg_dew_point": "25",
"avg_gust_wind": "",
"avg_max_temp": "38",
"avg_min_temp": "25",
"avg_precipitation": "0.00",
"avg_sea_level_pressure": "30.32",
"avg_temp": "31",
"avg_wind": "7"
},
"month": "1",
"state": "WA"
}
}
]
}
示例JSON1.json
{
"1948": [
{
"Jacksonville": {
"city": "Jacksonville",
"data": {
"avg_dew_point": "45",
"avg_gust_wind": "",
"avg_max_temp": "61",
"avg_min_temp": "44",
"avg_precipitation": "0.00",
"avg_sea_level_pressure": "30.13",
"avg_temp": "53",
"avg_wind": "8"
},
"month": "1",
"state": "FL"
}
},
{
"Indianapolis": {
"city": "Indianapolis",
"data": {
"avg_dew_point": "13",
"avg_gust_wind": "",
"avg_max_temp": "34",
"avg_min_temp": "13",
"avg_precipitation": "0.00",
"avg_sea_level_pressure": "30.17",
"avg_temp": "24",
"avg_wind": "12"
},
"month": "1",
"state": "IN"
}
}
],
"1949": [
{
"San Jose": {
"city": "San Jose",
"data": {
"avg_dew_point": "",
"avg_gust_wind": "",
"avg_max_temp": "52",
"avg_min_temp": "33",
"avg_precipitation": "0.02",
"avg_sea_level_pressure": "",
"avg_temp": "43",
"avg_wind": ""
},
"month": "1",
"state": "CA"
}
},
{
"Jacksonville": {
"city": "Jacksonville",
"data": {
"avg_dew_point": "55",
"avg_gust_wind": "",
"avg_max_temp": "73",
"avg_min_temp": "54",
"avg_precipitation": "0.00",
"avg_sea_level_pressure": "30.21",
"avg_temp": "63",
"avg_wind": "5"
},
"month": "1",
"state": "FL"
}
}
]
}
示例combinedJSON.json
{
"1948": [
{
"Seattle": {
"city": "Seattle",
"data": {
"avg_dew_point": "34",
"avg_gust_wind": "",
"avg_max_temp": "45",
"avg_min_temp": "35",
"avg_precipitation": "0.00",
"avg_sea_level_pressure": "30.22",
"avg_temp": "40",
"avg_wind": "8"
},
"month": "1",
"state": "WA"
}
},
{
"Chicago": {
"city": "Chicago",
"data": {
"avg_dew_point": "10",
"avg_gust_wind": "",
"avg_max_temp": "25",
"avg_min_temp": "11",
"avg_precipitation": "0.00",
"avg_sea_level_pressure": "30.17",
"avg_temp": "18",
"avg_wind": "12"
},
"month": "1",
"state": "IL"
}
},
{
"Jacksonville": {
"city": "Jacksonville",
"data": {
"avg_dew_point": "45",
"avg_gust_wind": "",
"avg_max_temp": "61",
"avg_min_temp": "44",
"avg_precipitation": "0.00",
"avg_sea_level_pressure": "30.13",
"avg_temp": "53",
"avg_wind": "8"
},
"month": "1",
"state": "FL"
}
},
{
"Indianapolis": {
"city": "Indianapolis",
"data": {
"avg_dew_point": "13",
"avg_gust_wind": "",
"avg_max_temp": "34",
"avg_min_temp": "13",
"avg_precipitation": "0.00",
"avg_sea_level_pressure": "30.17",
"avg_temp": "24",
"avg_wind": "12"
},
"month": "1",
"state": "IN"
}
}
],
"1949": [
{
"Houston": {
"city": "Houston",
"data": {
"avg_dew_point": "45",
"avg_gust_wind": "",
"avg_max_temp": "61",
"avg_min_temp": "44",
"avg_precipitation": "0.00",
"avg_sea_level_pressure": "30.15",
"avg_temp": "53",
"avg_wind": "12"
},
"month": "1",
"state": "TX"
}
},
{
"Seattle": {
"city": "Seattle",
"data": {
"avg_dew_point": "25",
"avg_gust_wind": "",
"avg_max_temp": "38",
"avg_min_temp": "25",
"avg_precipitation": "0.00",
"avg_sea_level_pressure": "30.32",
"avg_temp": "31",
"avg_wind": "7"
},
"month": "1",
"state": "WA"
}
},
{
"San Jose": {
"city": "San Jose",
"data": {
"avg_dew_point": "",
"avg_gust_wind": "",
"avg_max_temp": "52",
"avg_min_temp": "33",
"avg_precipitation": "0.02",
"avg_sea_level_pressure": "",
"avg_temp": "43",
"avg_wind": ""
},
"month": "1",
"state": "CA"
}
},
{
"Jacksonville": {
"city": "Jacksonville",
"data": {
"avg_dew_point": "55",
"avg_gust_wind": "",
"avg_max_temp": "73",
"avg_min_temp": "54",
"avg_precipitation": "0.00",
"avg_sea_level_pressure": "30.21",
"avg_temp": "63",
"avg_wind": "5"
},
"month": "1",
"state": "FL"
}
}
]
}
试试这个:
function mergeJson(target) {
for (var argi = 1; argi < arguments.length; argi++) {
var source = arguments[argi];
for (var key in source) {
if (!(key in target)) {
target[key] = [];
}
for (var i = 0; i < source[key].length; i++) {
target[key].push(source[key][i]);
}
}
}
return target;
}
演示:
这要归功于@djKianoosh的发现:)试试这个:
function mergeJson(target) {
for (var argi = 1; argi < arguments.length; argi++) {
var source = arguments[argi];
for (var key in source) {
if (!(key in target)) {
target[key] = [];
}
for (var i = 0; i < source[key].length; i++) {
target[key].push(source[key][i]);
}
}
}
return target;
}
演示:
这要归功于@djKianoosh:)迭代对象()并合并数组()。您是否研究过一个小型实用程序js库,如下划线或Lodash:它们有很多集合操作功能您可能会考虑进入jQuery extend,获取jquery的未统一版本,编写类似$.extend(true,{a:a},{b:b})的代码;按F12并在那里设置断点,加载页面并单步执行代码。涉及的代码相当多,但它在深度复制对象方面做得很好,不包含数组或函数的对象所涉及的函数有:extend、isPlainObject和type。这是否回答了您的问题?迭代对象()并合并数组()。您是否研究过一个小型实用程序js库,如下划线或Lodash:它们有很多集合操作功能您可能会考虑进入jQuery extend,获得jQuery的未统一版本,编写类似$.extend的代码(true,{a:“a”},{b:“b”});按F12并在那里设置断点,加载页面并单步执行代码。涉及的代码相当多,但它在深度复制对象方面做得很好,不包含数组或函数的对象所涉及的函数有:extend、isPlainObject和type。这是否回答了您的问题?我调整了JSFIDLE以使用下划线的zip/each/flant函数,看看它是否可以使用这些函数:@djKianoosh非常酷,感谢您对它的研究和理解。我把所有这些都放在一起,更新了我的答案,加入了小提琴,并给了你荣誉:)我从来没有使用过
下划线
,所以我从来没有想过这个解决方案。同时,显然欢迎您自己回答,因为它有效我调整了JSFIDLE以使用下划线的zip/each/flatte函数,看看使用这些函数是否有效:@djKianoosh非常酷,感谢您对它进行研究并解决它。我把所有这些都放在一起,更新了我的答案,加入了小提琴,并给了你荣誉:)我从来没有使用过下划线
,所以我从来没有想过这个解决方案。同时,显然欢迎你自己回答,因为它是有效的