从Python到Javascript的2D数组搜索
在Javascript中,这段代码的等价物是什么从Python到Javascript的2D数组搜索,javascript,python,arrays,Javascript,Python,Arrays,在Javascript中,这段代码的等价物是什么 array = ["James", "1", "3"] array2 = ["Bob", "2", "5"] mainArray = [array, array2] Person = "James" for element in mainArray: if (element[0] == Person): print Person + " " + "D=" + element[1] + " Z=" + element[
array = ["James", "1", "3"]
array2 = ["Bob", "2", "5"]
mainArray = [array, array2]
Person = "James"
for element in mainArray:
if (element[0] == Person):
print Person + " " + "D=" + element[1] + " Z=" + element[2]
我已经设法用Javascript创建了数组,但我不确定如何在JS函数中为for循环编码。for(var I=0;Ifor(var i = 0; i < mainArray.length; i++){
if(mainArray[i][0] == Person){
console.log(mainArray[i][1] + " " + mainArray[i][2]);
}
}
if(mainArray[i][0]==人){
log(mainArray[i][1]+“”+mainArray[i][2]);
}
}
试试这个:
var arr1 = ["James", "1", "3"],
arr2 = ["Bob", "2", "5"]
arrMain = [];
arrMain.push(arr1 , arr2);
for(x=0; x<arrMain.length; x+=1){
(arrMain[x][0] === 'James') &&
console.log(arrMain[x][0] + " " + "D=" + arrMain[x][1] + " Z=" + arrMain[x][2])
}
var arr1=[“James”,“1”,“3”],
arr2=[“Bob”,“2”,“5”]
arrMain=[];
arrMain.push(arr1,arr2);
对于(x=0;xarray=[“James”,“1”,“3”]
数组2=[“Bob”,“2”,“5”]
mainArray=array.concat(array2)
len=mainArray.length
对于(var i=0;i请检查下面的我的答案请查看您的答案。您提供的解决方案不会产生与原始python代码相同的结果。
array = ["James", "1", "3"]
array2 = ["Bob", "2", "5"]
mainArray = array.concat(array2)
len = mainArray.length
for(var i=0;i<len;++i){
if (mainArray[i] == "James"){
console.log(mainArray[i]);
}
}