Javascript 打开一个新窗口&；然后提交表格

如何打开新窗口，然后使用HTML\Javascript触发表单提交

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注意：target=“_blank”不是解决方案，因为它将响应重定向到新窗口，而我需要从新窗口触发提交操作

我会保留“\u blank”以触发新的选项卡/窗口，并使用jQuery和Ajax提交表单

带有表单的标准html页面

HTML

现在是Ajax页面

your-ajax-page-to-submit-the-form.php

ob_start(); //at the very beginning start output buffereing

$var_input1 = mysqli_real_escape_string($dbc, $_GET['input1']);
$var_input2 = mysqli_real_escape_string($dbc, $_GET['input2']);

$q = "INSERT INTO my_table (column1, column2) VALUES ('$input1', '$input2')";
$dbc = mysqli_connect('localhost', 'root', 'password', 'DB_Name') OR die('Could not connect because: '.mysqli_connect_error()); 
$r = mysqli_query($dbc, $q);

// bof if you want to output any results or values back to jQuery
$var = array(
    'result1_from_ajax' => $var_input1,
    'result2_from_ajax' => $var_input2
);
// eof if you want to output any results or values back to jQuery

// Must have
ob_end_clean(); // right before outputting the JSON, clear the buffer.
echo json_encode($var);

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No code example=我们无能为力您是想从原始窗口还是从您打开的窗口提交表单？我想从我打开的窗口提交表单。

$(document).ready(function() {
    $(document).on("click","#myFormButton", function() {

        var str = $("#myForm").serialize(); // This grabs all your form inputs by name and creates a string e.g. input1=someValue1&input2=someValue2 which you can use later for grabbing the $_GET variables.

        $.ajax({
        cache: false,
        url: 'ajax/your-ajax-page-to-submit-the-form.php?'+str,            
        type: 'POST',
        dataType: 'json',
        success: function(result) {
            alert("success");

            // Can get data from Ajax file by using array cretaed in the file (see below)
            $('#result1').val(result['result1_from_ajax']);

        },
        error : function () {
            alert("error");
        }
    });
});

ob_start(); //at the very beginning start output buffereing

$var_input1 = mysqli_real_escape_string($dbc, $_GET['input1']);
$var_input2 = mysqli_real_escape_string($dbc, $_GET['input2']);

$q = "INSERT INTO my_table (column1, column2) VALUES ('$input1', '$input2')";
$dbc = mysqli_connect('localhost', 'root', 'password', 'DB_Name') OR die('Could not connect because: '.mysqli_connect_error()); 
$r = mysqli_query($dbc, $q);

// bof if you want to output any results or values back to jQuery
$var = array(
    'result1_from_ajax' => $var_input1,
    'result2_from_ajax' => $var_input2
);
// eof if you want to output any results or values back to jQuery

// Must have
ob_end_clean(); // right before outputting the JSON, clear the buffer.
echo json_encode($var);