Javascript 如何在mongoose中更新子文档?

Javascript 如何在mongoose中更新子文档?,javascript,node.js,mongodb,mongoose,mongodb-query,Javascript,Node.js,Mongodb,Mongoose,Mongodb Query,我的模式如下所示: { "blogTitle":"Book" "blogContent":"demo" "blogrelatedLink":{ "relatedBloogId:"123", "relatedBlogTitle":"abc"` } } 我的代码是: const updateBlogs =

我的模式如下所示:

{
"blogTitle":"Book"
"blogContent":"demo"
"blogrelatedLink":{
    "relatedBloogId:"123",
    "relatedBlogTitle":"abc"`
    }
}
我的代码是:

const updateBlogs = async (req, res) => {
    const { blogId } = req.params;
    const re = /<("[^"]?"|'[^']?'|[^'">])*>/;

    if (re.test(req.params.blogTitle)) {
        sendError(400, "Unsuccessful", "Blog Title cannot be HTML", req, res);
    } else {
        try {
            let update = {};
            if (req.body.blogTitle) update.blogTitle = req.body.blogTitle;
            if (req.body.blogContent) update.blogContent = req.body.blogContent;
            let blog = await Blog.updateOne(
                { blogId },
                {
                    $set: update,
                },
                { runValidators: true }
            );
            sendResponse(200, "Successfull", blog, req, res);
        } catch (err) {
            sendError(400, "Blog can't be updated by given id", err, req, res);
        }
    }
};
const updateBlogs=async(req,res)=>{
const{blogId}=req.params;
常数re=/])*>/;
if(重新测试(要求参数标题)){
sendError(400,“不成功”,“博客标题不能是HTML”,req,res);
}否则{
试一试{
让update={};
如果(req.body.blogtile)update.blogtile=req.body.blogtile;
if(req.body.blogContent)update.blogContent=req.body.blogContent;
让blog=wait blog.updateOne(
{blogId},
{
$set:更新,
},
{runValidators:true}
);
sendResponse(200,“成功”,博客,请求,回复);
}捕捉(错误){
sendError(400,“博客无法通过给定id更新”,err,req,res);
}
}
};

更新子文档的代码是什么

更新键应为以下格式:只需将其放在更新查询之前

if (req.body.blogrelatedLink) {
  for (let key in req.body.blogrelatedLink) {
    update['blogrelatedLink.' + key] = req.body.blogrelatedLink[key];
  }
}

我试过了,但它仍然没有在我的mongoDB中更新,但谢谢@turivishal其他字段正在更新吗?blogId是mongo id吗?然后将其转换为对象类型
mongoose.Types.ObjectId(blogId)
blogId是我提供的,或者您可以将其作为自定义id,即使您可以在mongo中更改它,当我打开它的显示方式时,也可以这样(向下键)↓ blogRelatedLinks:数组(向下键)↓ 0:Object _id:objectid(1233454),relatedBlogId:12323454,relatedBlogTitle:“demo”我不确定你的代码中是否缺少一些内容,我刚刚在我的答案中添加了PlayGround工作链接,你只需控制台和调试你的代码。好的,我会检查,但谢谢@turivishal