Javascript 未捕获的语法错误:JS(ASP.NET)中的意外标识符
我有JS脚本从后端获取数据 这是剧本Javascript 未捕获的语法错误:JS(ASP.NET)中的意外标识符,javascript,jquery,asp.net,ajax,asp.net-mvc-4,Javascript,Jquery,Asp.net,Ajax,Asp.net Mvc 4,我有JS脚本从后端获取数据 这是剧本 <script> $(document).ready(function() { emaillist_update(); }); function emaillist_update() { var url = window.location.pathname; var id = url.substring(url.lastIndexOf('/') + 1); alert(id); $.ajax({
<script>
$(document).ready(function() {
emaillist_update();
});
function emaillist_update() {
var url = window.location.pathname;
var id = url.substring(url.lastIndexOf('/') + 1);
alert(id);
$.ajax({
url: '@Url.Action("Displayinfo", "Questions")',
type: 'Post',
dataType: 'Json',
data: {
ID: id
}
success: function(result) {
var info = result;
$("#vacancy").append("Мы ищем специалиста на вакансию:" + info.Vacancy);
},
error: function(result) {
alert('Error');
}
});
}
我有此错误Uncaught SyntaxError:此行url:'@url.Action(“Displayinfo”,“Questions”),
什么是麻烦?url似乎是正确的
感谢您的帮助尝试删除完整的行并重新键入(不要复制粘贴),可能有一些看不见的字符不,它在视图中@SatpalIt很有趣,但很有趣true@SatpalYes哥们儿,它works@Satpal
public ActionResult Displayinfo(int ID)
{
var res = db.Interview
.Where(x => x.Interview_Id == ID)
.Select(x => new
{
Vacancy = x.Vacancy.VacancyName,
Greeting = x.Greeting,
Detail = x.Detail
}).FirstOrDefault();
return Json(res, JsonRequestBehavior.AllowGet);
}