Javascript Node.js Socket.io-如何将消息发送到另一个侦听器中的套接字室?
我试图将消息发送到特定的房间,一旦客户机触发了“joinedRoom”侦听器,如果我将代码放在joinedRoom侦听器之外,代码就可以正常工作,否则它什么也不做 代码:Javascript Node.js Socket.io-如何将消息发送到另一个侦听器中的套接字室?,javascript,node.js,sockets,socket.io,Javascript,Node.js,Sockets,Socket.io,我试图将消息发送到特定的房间,一旦客户机触发了“joinedRoom”侦听器,如果我将代码放在joinedRoom侦听器之外,代码就可以正常工作,否则它什么也不做 代码: app.get('/room/:room/user/:user', function(req, res){ var room = { username: req.params.user, roomname: req.params.room }; res.render('r
app.get('/room/:room/user/:user', function(req, res){
var room = {
username: req.params.user,
roomname: req.params.room
};
res.render('room', room);
});
var users = {};
io.sockets.on('connection', function (socket) {
socket.on('joinedRoom', function(roomData){
socket.username = roomData.username;
socket.room = roomData.roomname;
console.log("Roomname: " + socket.room);
console.log("Username: " + socket.username);
socket.join(socket.room);
socket.broadcast.to(socket.room).emit('newUser', socket.username);
socket.on('disconnect', function(){
socket.broadcast.emit('userLeft', socket.username);
socket.leave(socket.room);
console.log('Connection id: ' + socket.id);
});
});
});
客户端代码:
var socket, roomname, ioRoom;
var socket = io.connect('http://localhost:3000');
socket.on('enterRoom', function(roomname){
console.log("ENTERED ROOM: " + roomname);
});
socket.on('newUser', function(username){
pushUserName(username);
pushUserStatus(username, ' has joined the room <br/>')
});
socket.on('newRoom', function(data){
alert(data)
});
socket.on('userLeft', function(username){
pushUserStatus(username, ' has left the room <br/>')
})
function pushUserName(username){
var el = document.getElementById("username");
el.innerHTML += username + '<br/>';
}
function pushUserStatus(username, message){
var el = document.getElementById("joined");
el.innerHTML += username + message;
}
我看到了文档和一些示例代码,一切似乎都是正确的(当涉及到简单的语法时),我是否遗漏了一些简单的东西
谢谢!我认为您需要在连接事件侦听器之外注册断开连接事件侦听器 代码:
对于那些可能有类似问题的人,代码基本上是正确的,但我忽略了这一点: 而不是:
socket.emit('joinedRoom', roomData);
应该是:
socket.on('connect', function(){
socket.emit('joinedRoom', roomData);
})
:)Hello@Yod谢谢你的帮助,我按照你的建议做了,但没有成功,有趣的是,如果我完全删除joinedRoom侦听器,它就会成功。。。。
socket.emit('joinedRoom', roomData);
socket.on('connect', function(){
socket.emit('joinedRoom', roomData);
})