格式化程序上的JqGrid问题
我正在使用这个jqgrid:格式化程序上的JqGrid问题,jqgrid,Jqgrid,我正在使用这个jqgrid: $("#griglia-navgrid").jqGrid( { colNames:[...], colModel:[ {name:'ZMENG_SOR_VRKME_PREC', index:'ZMENG_SOR_VRKME_PREC', width:'5', sortable:false, formatter:numFormat}, ], ... footerrow:tr
$("#griglia-navgrid").jqGrid( {
colNames:[...],
colModel:[ {name:'ZMENG_SOR_VRKME_PREC', index:'ZMENG_SOR_VRKME_PREC', width:'5', sortable:false, formatter:numFormat}, ],
...
footerrow:true,
afterInsertRow: function(id){ $("#griglia-navgrid").jqGrid('setCell',id,'ZPARVW_Z1','',{'text-decoration':'underline'}); },
loadComplete: function () {
var $this = $(this),
sum = $this.jqGrid("getCol", "ZMENG_SOR_VRKME", false, "sum"),
$footerRow = $(this.grid.sDiv).find("tr.footrow"),localData = $this.jqGrid("getGridParam", "data"),totalRows = localData.length,totalSum = 0, $newFooterRow, i;
$newFooterRow = $(this.grid.sDiv).find("tr.myfootrow");
if ($newFooterRow.length === 0) {
$newFooterRow = $footerRow.clone();
$newFooterRow.removeClass("footrow").addClass("myfootrow ui-widget-content");
$newFooterRow.children("td").each(function () {
this.style.width = ""; // remove width from inline CSS
});
$newFooterRow.insertAfter($footerRow);
}
for (i = 0; i < totalRows; i++) {
if(localData[i].ZMENG_SOR_VRKME.search("-") == -1){
totalSum += parseFloat(localData[i].ZMENG_SOR_VRKME);}
else{
totalSum -= parseFloat(localData[i].ZMENG_SOR_VRKME);
}
}
$newFooterRow.find(">td[aria-describedby=" + this.id + "_ZPARVW_Z1_NAME]").text("Totale:");
$newFooterRow.find(">td[aria-describedby=" + this.id + "_ZMENG_SOR_VRKME]").text(
$.fmatter.util.NumberFormat(totalSum, $.jgrid.formatter.number.decimalSeparator=',')
);
}
}); //jqGrid
function numFormat( cellvalue, options, rowObject ){
return cellvalue.replace(".",",");
}
$(“#格里利亚导航网格”).jqGrid({
colNames:[…],
colModel:[{name:'zming_SOR_VRKME_PREC',index:'zming_SOR_VRKME_PREC',width:'5',可排序:false,格式化程序:numFormat},],
...
是的,
afterInsertRow:function(id){$(“#griglia navgrid”).jqGrid('setCell',id,'ZPARVW_Z1','','',{'text-decoration':'underline'}),
loadComplete:函数(){
变量$this=$(this),
sum=$this.jqGrid(“getCol”,“ZMENG_SOR_VRKME”,false,“sum”),
$footerRow=$(this.grid.sDiv).find(“tr.footrow”),localData=$this.jqGrid(“getGridParam”,“data”),totalRows=localData.length,totalSum=0,$newFooterRow,i;
$newFooterRow=$(this.grid.sDiv).find(“tr.myfooterow”);
如果($newFooterRow.length==0){
$newFooterRow=$footerRow.clone();
$newFooterRow.removeClass(“footrow”).addClass(“myfootrow ui小部件内容”);
$newFooterRow.children(“td”)。每个(函数(){
this.style.width=”“;//从内联CSS中删除宽度
});
$newFooterRow.insertAfter($footerRow);
}
对于(i=0;itd[aria descripbedby=“+this.id+”)”\u ZPARVW\u Z1\u NAME]”);
$newFooterRow.find(“>td[aria descripbedby=“+this.id+”)”\u ZMENG\u SOR\u VRKME]”。文本(
$.fmatter.util.NumberFormat(总和,$.jgrid.formatter.number.decimalSeparator=',')
);
}
}); //jqGrid
函数numFormat(单元格值、选项、行对象){
返回cellvalue。替换(“.”、“,”);
}
它适用于Safari和Chrome。在firefox中,我有一个错误:“ReferenceError:numFormat未定义”
如何解决此问题?格式化程序函数应放在JQGrid定义之前。
然后它就可以工作了。您能显示其余的代码吗?其中调用了$(“#grid”).jqGrid(),它是否在函数本身内部?
“ReferenceError:未定义”
是在未找到预期对象引用时发现的常规错误。请尝试在jqgrid定义之前定义函数“numFormat”。如果这不起作用,请更新有问题的jQGrid的整个代码,其中可能也有遗漏。Tks Pranav,我在jQGrid前面放了函数“numFormat”。。非常喜欢:D