Jquery 上传图像时从浏览窗口选择图像后自动提交表单

我想上传图像并将其存储在数据库中。但当我点击图像打开浏览文件对话框时，表单已经提交。但我想在选择图像后提交表单

这是我的密码

<form>

<input type="file" id="my_file" style="display:none;" />
<input type="image" src="albert-einstein-bike.jpg" width="90px" height="200" />
</form>

 <script>

$("input[type='image']").click(function() {
$("input[id='my_file']").click();
});
</script>

$（“输入[type='image']”）。单击（函数（）{
$（“输入[id='my_file']）。单击（）；
});

希望这样的东西能帮你，伙计……）

html

<div id='preview'></div>
    <form id="imageform" method="post" enctype="multipart/form-data" action='ajaximage.php'>
    <input type="file" name="photoimg" id="photoimg" />
     </form>

ajaximage.php

if(isset($_POST) and $_SERVER['REQUEST_METHOD'] == "POST")
{
$name = $_FILES['photoimg']['name'];
$size = $_FILES['photoimg']['size'];
$tmp = $_FILES['photoimg']['tmp_name'];
$path = "uploads/";
move_uploaded_file($tmp, $path.$name) //Stores the image in the uploads folder
}

---

brother i无法提交表单。请检查iTunesCught类型错误：对象[Object Object]没有“live”方法使用

而不是
live
mate:）未捕获类型错误：对象[Object Object]没有方法“ajaxForm”，您可能没有正确添加脚本。请检查是否添加了jquery form.js

if(isset($_POST) and $_SERVER['REQUEST_METHOD'] == "POST")
{
$name = $_FILES['photoimg']['name'];
$size = $_FILES['photoimg']['size'];
$tmp = $_FILES['photoimg']['tmp_name'];
$path = "uploads/";
move_uploaded_file($tmp, $path.$name) //Stores the image in the uploads folder
}