Jquery 自动完成不显示返回的结果
虽然php代码返回json结果,但我无法获得要显示的jquery自动完成的结果。jquery代码如下所示:Jquery 自动完成不显示返回的结果,jquery,autocomplete,jquery-ui-autocomplete,Jquery,Autocomplete,Jquery Ui Autocomplete,虽然php代码返回json结果,但我无法获得要显示的jquery自动完成的结果。jquery代码如下所示: $("#newName").autocomplete({ source: function(request, response) { $.ajax({ url: root + "/assets/php/autocomplete.php", dataType: "json", data: {
$("#newName").autocomplete({
source: function(request, response) {
$.ajax({
url: root + "/assets/php/autocomplete.php",
dataType: "json",
data: {
term : request.term,
field : "name"
},
success: function(data) {
response(data);
}
});
});
php代码是:
while ($row = $result->fetch(PDO::FETCH_ASSOC)) {
$row_array['value'] = $row[$field];
array_push($return_arr,$row_array);
}
echo json_encode($return_arr);
在Firebug中检查结果时,我得到如下响应:
[{“值”:“jdoe”}]
但是,我从未在html页面中看到建议列表。任何关于问题所在的建议
谢谢,
AB你试过这个吗
data: {
term : request.value,
field : "name"
},
您的数组键是
'value'
,而不是'term'
我通过在主css文件中添加一个用于自动完成的z索引样式来修复此问题。现在一切正常
.ui-autocomplete {
z-index: 100;
}
在PHP代码中,尝试更改“标签”的“值”:
while ($row = $result->fetch(PDO::FETCH_ASSOC)) {
$row_array['label'] = $row[$field];
array_push($return_arr,$row_array);
}
echo json_encode($return_arr);
我不知道为什么,但这似乎很重要。我将附上为我工作的例子。在我的例子中,我必须通过一个PHP文件从jQuery进行MySQL连接。我想做一个自动完成字段,你可以写一个用户名,当你点击用户名时,相关字段(姓名,姓氏,电子邮件…)被填充。这是我的密码:
HTML代码:
<html lang="en">
<head>
<link rel="stylesheet" href="http://code.jquery.com/ui/1.10.3/themes/smoothness/jquery-ui.css" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"
</script>
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script src="http://code.jquery.com/ui/1.10.3/jquery-ui.js"></script>
<!--Here there is my jQuery script-->
<script type="text/javascript" src="scripts/myjQuery.js"></script>
<title>EXAMPLE AUTOCOMPLETE</title>
</head>
<body>
<h1>CREATING A NEW CASE</h1>
<form id='newcase' action="#" method="POST" name="newcase">
<label>Add Nickname </label>
<input class="input-250" type="text" id="nickname" name="nickname"><br/>
<label>First Name </label>
<input class="input-250" type="text" id="firstname" name="firstname"><br/>
<label>Surname </label>
<input class="input-250" type="text" id="surn" name="surn"><br/>
<label>Organisation</label>
<input class="input-250"type="text" id="organisation" name="organisation"><br/>
<label>E-Mail Address </label>
<input class="input-250" type="text" id="email" name="email"><br/>
</form>
</body>
</html>
$(document).ready(function(){
$('#nickname').autocomplete({
//Here I call the PHP file and the method inside this file, separated by '/'.
//You should manage it somehow to make this possible.
//I have managed it whith a PHP file called index.php, that gets whatever it comes
//from the URL after the 'rt' and it separates it by the slash,
//being the first value the name of the file, and the second value the name of the
//method.
source:'index.php?rt=jscallsController/listNicknameUsers',
minLength:1,
select: function(evt, ui)
{
// when a username is selected, populate related fields in this form
document.getElementById('firstname').value = ui.item.firstname;
document.getElementById('surn').value = ui.item.surname;
document.getElementById('organisation').value = ui.item.org;
document.getElementById('email').value = ui.item.mail;
}
});
});
<?php
class jscallsController{
public function listNicknameUsers(){
$hostdb = 'localhost';
$namedb = 'tests';
$userdb = 'username';
$passdb = 'password';
$term = trim(strip_tags($_GET['term']));
$users = 'table_users';
$data = array();
try {
// Connect and create the PDO object
$conn = new PDO("mysql:host=$hostdb; dbname=$namedb", $userdb, $passdb);
// Sets encoding UTF-8
$conn->exec("SET CHARACTER SET utf8");
//Define and perform the SQL SELECT query
$sql = "SELECT u_name, u_fname, u_surname, u_organisation, u_email FROM $users
WHERE u_name LIKE '$term%'";
$result = $conn->query($sql);
// If the SQL query is succesfully performed ($result not false)
if($result !== false) {
// Number of returned rows
$rows = $result->rowCount();
//If exists, returns 1
if($rows > 0){
foreach($result as $user) {
/*The first position of the array needs to be called 'label',
otherwise it will not show anything in the HTML field
where the autocomplete is done.*/
$data[] = array(
'label' => $user['u_name']." (".$user['u_fname']." ".$user['u_surname'].")" ,
'firstname' =>$user['u_fname'],
'surname' => $user['u_surname'],
'org' => $user['u_organisation'],
'mail' => $user['u_email']
);
}
}
}
//Disconnect
$conn = null;
//We send back the array to the jQuery
echo json_encode($data);
}
catch(PDOException $e) {
echo $e->getMessage();
}
}
}
?>
和PHP文件jscallsController.PHP:
<html lang="en">
<head>
<link rel="stylesheet" href="http://code.jquery.com/ui/1.10.3/themes/smoothness/jquery-ui.css" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"
</script>
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script src="http://code.jquery.com/ui/1.10.3/jquery-ui.js"></script>
<!--Here there is my jQuery script-->
<script type="text/javascript" src="scripts/myjQuery.js"></script>
<title>EXAMPLE AUTOCOMPLETE</title>
</head>
<body>
<h1>CREATING A NEW CASE</h1>
<form id='newcase' action="#" method="POST" name="newcase">
<label>Add Nickname </label>
<input class="input-250" type="text" id="nickname" name="nickname"><br/>
<label>First Name </label>
<input class="input-250" type="text" id="firstname" name="firstname"><br/>
<label>Surname </label>
<input class="input-250" type="text" id="surn" name="surn"><br/>
<label>Organisation</label>
<input class="input-250"type="text" id="organisation" name="organisation"><br/>
<label>E-Mail Address </label>
<input class="input-250" type="text" id="email" name="email"><br/>
</form>
</body>
</html>
$(document).ready(function(){
$('#nickname').autocomplete({
//Here I call the PHP file and the method inside this file, separated by '/'.
//You should manage it somehow to make this possible.
//I have managed it whith a PHP file called index.php, that gets whatever it comes
//from the URL after the 'rt' and it separates it by the slash,
//being the first value the name of the file, and the second value the name of the
//method.
source:'index.php?rt=jscallsController/listNicknameUsers',
minLength:1,
select: function(evt, ui)
{
// when a username is selected, populate related fields in this form
document.getElementById('firstname').value = ui.item.firstname;
document.getElementById('surn').value = ui.item.surname;
document.getElementById('organisation').value = ui.item.org;
document.getElementById('email').value = ui.item.mail;
}
});
});
<?php
class jscallsController{
public function listNicknameUsers(){
$hostdb = 'localhost';
$namedb = 'tests';
$userdb = 'username';
$passdb = 'password';
$term = trim(strip_tags($_GET['term']));
$users = 'table_users';
$data = array();
try {
// Connect and create the PDO object
$conn = new PDO("mysql:host=$hostdb; dbname=$namedb", $userdb, $passdb);
// Sets encoding UTF-8
$conn->exec("SET CHARACTER SET utf8");
//Define and perform the SQL SELECT query
$sql = "SELECT u_name, u_fname, u_surname, u_organisation, u_email FROM $users
WHERE u_name LIKE '$term%'";
$result = $conn->query($sql);
// If the SQL query is succesfully performed ($result not false)
if($result !== false) {
// Number of returned rows
$rows = $result->rowCount();
//If exists, returns 1
if($rows > 0){
foreach($result as $user) {
/*The first position of the array needs to be called 'label',
otherwise it will not show anything in the HTML field
where the autocomplete is done.*/
$data[] = array(
'label' => $user['u_name']." (".$user['u_fname']." ".$user['u_surname'].")" ,
'firstname' =>$user['u_fname'],
'surname' => $user['u_surname'],
'org' => $user['u_organisation'],
'mail' => $user['u_email']
);
}
}
}
//Disconnect
$conn = null;
//We send back the array to the jQuery
echo json_encode($data);
}
catch(PDOException $e) {
echo $e->getMessage();
}
}
}
?>
我也有同样的问题。
对于我来说,解决方案是将z-index设置为更高的值,就像这样
.ui-autocomplete
{
position:absolute;
cursor:default;
z-index:1001 !important
}
有些元素隐藏了自动完成表单。
(在我的应用程序中)试试这个,它对我有用
.ui-front {
z-index: 1500 !important;
}
只是想和大家分享解决我问题的方法 这很常见,但可能会帮助其他人 除了在项目中包含
jqueryui.js
之外始终确保还包括jqueryui.css
<link href="Stylesheets/jquery-ui.css" rel="stylesheet" />
<script src="Scripts/jquery-ui.js"></script>
刚刚尝试了这一更改,但没有任何效果。在查看Firebug时,我仍然以[{“value”:“jdoe”}]的形式返回一个响应,但结果不会显示在html页面中。请尝试删除此字段:“name”。您的输入Id是newName?这似乎是CSS样式的问题。如果我删除所有CSS样式表,我会在文本框旁边看到以下消息:1结果可用,使用上下箭头键刚发现结果显示在下拉列表中,但它隐藏在表单后面。我必须移动表格才能看到它。如果我只能发现jquery ui.css中的where?使用firebug检查表单这为我修复了它,但我的z索引要高得多,因为我是在一个模式“弹出窗口”中执行此操作的。因此,请确保测试您的z索引:console.log(“z索引:+$(.selector”).zIndex())代码>在某些情况下,其z索引也为:9999999999;;-)我喜欢您的实现/*数组的第一个位置需要称为“标签”,否则它将不会在HTML字段中显示完成自动完成的任何内容。*/是救世主。。谢谢