Jquery 在我的例子中，如何从Json Stringify读取值？

验证用户登录后，如果失败，将显示以下错误消息

jquery

console.log('Full error  = ' + JSON.stringify(showError));
console.log('test 1 =' + showError.responseText);

错误消息

Full error  = {"readyState":4,"responseText":"{\"error\":\"invalid_grant\",\"error_description\":\"The user name or password is incorrect.\"}","responseJSON":{"error":"invalid_grant","error_description":"The user name or password is incorrect."},"status":400,"statusText":"Bad Request"}


test 1 ={"error":"invalid_grant","error_description":"The user name or password is incorrect."}

我只想显示

用户名或密码不正确

信息

---

我已经检查了这个链接，因为它是一个JSON字符串，所以您必须解析

responseText

属性

console.log(JSON.parse(showError.responseText).error_description);

// or using bracket notation
console.log(JSON.parse(showError.responseText)['error_description']);

var-shortError={“readyState”：4，“responseText”：“{”错误“：\”无效的授权“，\”错误描述“：\”用户名或密码不正确。\“}”，“responseJSON:{”错误“：”无效的授权“，”错误描述“：”用户名或密码不正确“，}，”状态“：”400，“状态文本“：”错误请求“}；
log（JSON.parse（shourror.responseText）.error\u说明）您可以使用JSON.parse方法以字符串格式解析JSON数据。它将返回一个JSON对象。在您的示例中

var response = JSON.stringify('{"readyState":4,"responseText":"{\"error\":\"invalid_grant\",\"error_description\":\"The user name or password is incorrect.\"}","responseJSON":{"error":"invalid_grant","error_description":"The user name or password is incorrect."},"status":400,"statusText":"Bad Request"}
')
var error_message = response.responseText.error_description

错误消息变量包含您的错误消息
是否可以尝试console.log（淋浴错误.响应文本.错误描述）@Satya我已经试过了兄弟，它是未定义的