行中带有来自ajax源代码的变量的jQuery Datatable按钮
我正在尝试使用以下代码在datatable行中添加一个按钮:行中带有来自ajax源代码的变量的jQuery Datatable按钮,jquery,datatables,Jquery,Datatables,我正在尝试使用以下代码在datatable行中添加一个按钮: $("#tbllandinfo").DataTable({ searching: false, ordering: false, paging: false, bInfo: false, ajax: { url: '/land_and_crops/id/' + $("#eid")
$("#tbllandinfo").DataTable({
searching: false,
ordering: false,
paging: false,
bInfo: false,
ajax: {
url: '/land_and_crops/id/' + $("#eid").val(),
dataSrc: '',
},
columns: [
{ data: 'ldacres' },
{ data: 'ldyields' },
{ data: 'cname' },
{
sortable:false,
defaultContent: "<button class='btn btn-danger btn-delete form-control pull-right' dbcolid='ldid' dbcolidval= dbtable='land_det'>X</button>",
}
]
});
使用render而不是defaultContent。请参见此处讨论:()使用渲染而不是defaultContent。见此处讨论:()
{"ldid":4,"ldentity":7,"ldacres":"5.00","ldyields":2,"ldcrop":5,"cname":"RICE"},
{"ldid":7,"ldentity":7,"ldacres":"10.00","ldyields":1,"ldcrop":6,"cname":"MAIZE",
{"ldid":6,"ldentity":7,"ldacres":"4.00","ldyields":1,"ldcrop":3,"cname":"CORN"}