Jquery 如何通过ajax重新加载数据
可能重复:Jquery 如何通过ajax重新加载数据,jquery,ajax,database,servlets,Jquery,Ajax,Database,Servlets,可能重复: 我有以下代码: public class IndexServlet extends HttpServlet { MoodService moodService; public IndexServlet() { moodService = new MoodService(); } /** * Accepts the request and sends it to the dispatcher which takes th
我有以下代码:
public class IndexServlet extends HttpServlet {
MoodService moodService;
public IndexServlet() {
moodService = new MoodService();
}
/**
* Accepts the request and sends it to the dispatcher which takes the database data and presents it as HTML
*/
@Override
protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
List<Mood> moodList = moodService.findLastMoods(25); //my way of getting data from database
req.setAttribute("moodList", moodList);
RequestDispatcher requestDispatcher =req.getRequestDispatcher("index.jsp");
requestDispatcher.forward(req, resp);
}
}
公共类IndexServlet扩展了HttpServlet{
情绪服务情绪服务;
公共IndexServlet(){
moodService=新的moodService();
}
/**
*接受请求并将其发送给dispatcher,dispatcher接收数据库数据并将其显示为HTML
*/
@凌驾
受保护的void doGet(HttpServletRequest-req,HttpServletResponse-resp)抛出ServletException,IOException{
List moodList=moodService.findLastMoods(25);//我从数据库获取数据的方法
请求setAttribute(“moodList”,moodList);
RequestDispatcher RequestDispatcher=req.getRequestDispatcher(“index.jsp”);
转发(req,resp);
}
}
以及index.jsp文件:
<html>
<head>
<title>Previous 25 entries:</title>
<style type="text/css">
#container {width:1200px; margin-left:auto; margin-right: auto;}
#tableheader {width:900px; text-align: center;}
.field {text-align:center; width:300px;}
</style>
</head>
<body style="background-color: black;">
<div id="container">
<table border="1" bordercolor="#FFCC00" width="900" height="80" cellpadding="3" cellspacing="3" style="border-top-left-radius: 15px; border-top-right-radius: 15px; text-align: center; margin-left:auto; margin-right: auto; background-color:#FFFFCC; font-size: 33px; font-family: Monotype Corsiva ">
<tr>
<td style="border-top-left-radius: 10px; border-top-right-radius: 10px;">PREVIOUS 25 ENTRIES:</td>
</tr>
</table>
<%
List<Mood> moodList = (List<Mood>) request.getAttribute("moodList");
for (Mood mood : moodList) {
Integer a = mood.getMoodId();
String moodId = new String();
switch (a) {
case 1:
moodId = "Happy";
break;
case 2:
moodId = "Sad";
break;
case 3:
moodId = "Lonely";
break;
case 4:
moodId = "Angry";
break;
case 5:
moodId = "In Love";
break;
case 6:
moodId = "Content";
break;
} %>
<table id="table" border="1" bordercolor="#FFCC00" width="900" cellpadding="3" cellspacing="3" style="text-align: center; margin-left:auto; margin-right: auto; background-color:#FFFFCC;">
<tr>
<td class="field"> <%=mood.getUserId()%></td>
<td class="field"> <%=moodId%></td>
<%Date date = new Date(mood.getTime());
SimpleDateFormat sdf = new SimpleDateFormat("dd:MM:yyyy hh:mm:ss");
String sDate = sdf.format(date);
%>
<td class="field"> <%=sDate%></td>
</tr>
</table>
<%
}
%>
</div>
</body>
</html>
前25项:
#容器{宽度:1200px;左边距:自动;右边距:自动;}
#表格标题{宽度:900px;文本对齐:居中;}
.field{文本对齐:中心;宽度:300px;}
前25项:
我的问题是:
我如何在其中实现AJAX,以便每30秒用新数据刷新一次表,显示数据库中的最后25个条目?我更喜欢使用jquery,看看我用它做的每件事都比不使用jquery简单得多
我对AJAX一无所知,这是我第一次使用它(我刚刚开始学习),因此如果有人能给我一个关于如何使用AJAX的分步教程,我将不胜感激。(或者至少向我展示我想要的代码,我可以对其进行反向工程,可能:))
MoodService是我自己处理数据库的类(它的工作方式与这种情况无关,唯一重要的是我需要在加载站点后将数据重新加载到表中)
谢谢你的帮助!:) 我建议您看看这本非常简单实用的教程:
您需要三件事: