Jquery 异常消息::必须返回关系实例。laravel中的数据表错误
我试图在Jquery 异常消息::必须返回关系实例。laravel中的数据表错误,jquery,ajax,laravel,datatable,Jquery,Ajax,Laravel,Datatable,我试图在数据表上显示数据,我收到以下错误异常消息:App/Transaction::shipping\u address必须返回关系实例 ->addColumn('shipping_address', function ($row) { if($row->shipping_address==NULL || trim($row->shipping_address)=='') { return "Un Assigned"; } e
数据表上显示数据,我收到以下错误异常消息:App/Transaction::shipping\u address必须返回关系实例
->addColumn('shipping_address', function ($row) {
if($row->shipping_address==NULL || trim($row->shipping_address)=='') {
return "Un Assigned";
} else {
return $row->shipping_address;
}
})
shipping\u address
是列还是关系?