Json 如何在单个API调用中定义swagger中的查询和主体参数
API在主体和查询中有参数,我需要在swagger中定义它,如下所示:Json 如何在单个API调用中定义swagger中的查询和主体参数,json,node.js,yaml,swagger,Json,Node.js,Yaml,Swagger,API在主体和查询中有参数,我需要在swagger中定义它,如下所示: parameters: [ { "name": "businessCode", "in": "query", "required": true, "type": "string", }, { "name":"clientCode", "in":"query", "required":true, "type":"string", }, {
parameters: [
{
"name": "businessCode",
"in": "query",
"required": true,
"type": "string",
},
{
"name":"clientCode",
"in":"query",
"required":true,
"type":"string",
},
{
"name":"client",
"in":"body",
"required":true,
}
]
我认为这很容易,你已经举了一个例子。这是另一个恰当的例子
parameters: [{
name: "id",
description: "id of something",
required: true,
type: "Id",
paramType: "query"
},
{
name: "Body",
description: "any data",
required: true,
type: "User", //define this model in model file
paramType: "body"
}]
我认为这很容易,你已经举了一个例子。这是另一个恰当的例子
parameters: [{
name: "id",
description: "id of something",
required: true,
type: "Id",
paramType: "query"
},
{
name: "Body",
description: "any data",
required: true,
type: "User", //define this model in model file
paramType: "body"
}]