Json 错误:键入';任何';没有带Swift 4的阿拉莫菲尔下标成员

Json 错误:键入';任何';没有带Swift 4的阿拉莫菲尔下标成员,json,swift,alamofire,Json,Swift,Alamofire,我尝试过许多解决方案,但都没有成功。我试图传递json数据并返回用户值 型号: import Foundation class UserModel: NSObject { var UserID: String! var Name: String! init(UserID: String, Name: String) { super.init() self.UserID = UserID self.Name = Name } } guard let ur

我尝试过许多解决方案,但都没有成功。我试图传递json数据并返回用户值

型号:

import Foundation

class UserModel: NSObject {

var UserID: String!
var Name: String!

init(UserID: String, Name: String) {
    super.init()

    self.UserID = UserID
    self.Name = Name

}
}
    guard let url = URL(string: "https://api.com/api.php?PatientList") else { return }
    var request = URLRequest(url: url)

    request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Accept")
    request.httpMethod = "POST"

    let pinPost = "&Token=\(token)"
    request.httpBody = pinPost.data(using: .utf8)

    Alamofire.request(request).responseJSON { (response) in
        if let dict = response.result.value as? Dictionary<String, AnyObject> {
            if let datas = dict["Data"] as? NSArray {
                for data in datas {

                    let users = UserModel(UserID: data["PatientID"], Name: data["DisplayName"])

                }
            }
        }
    }
提取功能:

import Foundation

class UserModel: NSObject {

var UserID: String!
var Name: String!

init(UserID: String, Name: String) {
    super.init()

    self.UserID = UserID
    self.Name = Name

}
}
    guard let url = URL(string: "https://api.com/api.php?PatientList") else { return }
    var request = URLRequest(url: url)

    request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Accept")
    request.httpMethod = "POST"

    let pinPost = "&Token=\(token)"
    request.httpBody = pinPost.data(using: .utf8)

    Alamofire.request(request).responseJSON { (response) in
        if let dict = response.result.value as? Dictionary<String, AnyObject> {
            if let datas = dict["Data"] as? NSArray {
                for data in datas {

                    let users = UserModel(UserID: data["PatientID"], Name: data["DisplayName"])

                }
            }
        }
    }
你需要

if let datas = dict["Data"] as? [[String:Any]] {
而不是

if let datas = dict["Data"] as? NSArray {
由于数组元素的类型为
Any
,无法在此处订阅
data[“PatientID”]
data[“DisplayName”]

Alamofire.request("request").responseJSON { (response) in
    if let dict = response.result.value as? [String:Any] {
        if let datas = dict["Data"] as? [[String:Any]] {
            for data in datas {
                if let id = data["PatientID"] as? Int , let name = data["DisplayName"] as? String {
                  let users = UserModel(UserID:id, Name: name)
                } 
            }
        }
    }
}

也可以考虑使用<代码> CODEPEN/CONDE>解析响应

struct Root: Codable {
    let data: [UserModel]
    enum CodingKeys: String, CodingKey {
       case data = "Data"
    }
}

struct UserModel: Codable {
    let patientID: Int
    let displayName: String

    enum CodingKeys: String, CodingKey {
        case patientID = "PatientID"
        case displayName = "DisplayName"
    }
}

Alamofire.request("request").responseData{ (response) in
    if let data = response.data  {

        do {
            let res = try JSONDecoder().decode(Root.self, from: data)
            print(res.data)
        }
        catch {
            print(error)
        }
    }
}

正确的答案是

{“数据”:[{“显示名称”:“杰瑞·史密斯”,“德·伯德”:“1987年8月9日”}]


当我尝试使用
Codable
解决方案:
dataCorrupted(Swift.DecodingError.Context(codingPath:[],debugDescription:“给定的数据不是有效的JSON.”,underyingerror:Optional(error Domain=nscocaerordomain code=3840“No value.”UserInfo={NSDebugDescription=No value.})时,我遇到了这个错误
那么你的json无效我已经添加了我的json的照片,请你看一下。将其作为字符串发布,因为我会让你知道正确的编辑,而且没有PatientID密钥,所以请用DOB替换它