Warning: file_get_contents(/data/phpspider/zhask/data//catemap/5/ember.js/4.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Json 游戏中未检索POST数据!框架_Json_Post_Playframework - Fatal编程技术网

Json 游戏中未检索POST数据!框架

Json 游戏中未检索POST数据!框架,json,post,playframework,Json,Post,Playframework,我有一个视图发布了一组有效的json,比如 [{"profile_sfid":"00eA0000000l3v7IAA", "object":[{"name":"null", "viewable":[],"editable":[]},{"name":"account", "viewable":["Object Type","Salesforce ID"],"editable":["Test Multi","Test Checkbox"]},{"name":"contact", "viewable"

我有一个视图发布了一组有效的json,比如

[{"profile_sfid":"00eA0000000l3v7IAA", "object":[{"name":"null", "viewable":[],"editable":[]},{"name":"account", "viewable":["Object Type","Salesforce ID"],"editable":["Test Multi","Test Checkbox"]},{"name":"contact", "viewable":["Object Type","Salesforce ID"],"editable":["Test Multi","Test Checkbox"]}]}]
在/saveAssignments处创建路线。post操作将返回一条200成功消息,但控制器方法将logger语句上的json返回null

public static void saveAssignments(JsonElement json)
{
    Logger.debug("Hey guys, here is my json! " + json);
}
对JsonElement使用以下GSONBinder

@Global
public class GsonBinder implements TypeBinder<JsonElement> {   

@Override   
public Object bind(String name, Annotation[] annotations, String value,  Class actualClass, Type genericType) throws Exception 
{       
    return new JsonParser().parse(value); 
}
}

如果有任何帮助,我将不胜感激,因为我不确定它为什么不能正确接受这一点。

我正在做类似的事情,使用一个pojo类,该类的结构与示例中要接收的json对象相同,即Player类:

public class Player {
    public String name;
    ...
}

public static void addPlayerJSON(JsonObject body) {
    Gson gson = new Gson();
    Player newPlayer = gson.fromJson(body, Player.class);
    Logger.debug("Player name: " + newPlayer.name);
    ...
}

newPlayer对象从json解析数据。

如果您传递一个参数json={your json},您将在服务器端接收它。或者将json参数重命名为body,以便它可以使用在请求正文中发布的json