Json 将结果保存到新的csv文件,而不是println Groovy

Json 将结果保存到新的csv文件,而不是println Groovy,json,groovy,export-to-csv,Json,Groovy,Export To Csv,如何将groovy脚本的结果保存到新文件中?C:/temp/all1.csv。我想将json文件解析为csv,脚本工作正常,但我不知道如何将结果保存到新文件中。请帮忙 import groovy.json.* import java.io.File def json =''' { "expand": "schema,names", "startAt": 0, "maxResults": 50,

如何将groovy脚本的结果保存到新文件中?C:/temp/all1.csv。我想将json文件解析为csv,脚本工作正常,但我不知道如何将结果保存到新文件中。请帮忙

import groovy.json.*
import java.io.File
def json ='''
{
   "expand": "schema,names",
   "startAt": 0,
   "maxResults": 50,
   "total": 21,
   "issues":    [
            {
         "expand": "operations,versionedRepresentations",
         "id": "217580",
         "self": "issue/217580",
         "key": "ART-4070",
         "fields": {"summary": "#[ART] Pre.3 Verification \\"S\\""}
      },
            {
         "expand": "operations,versionedRepresentations",
         "id": "217579",
         "self": "issue/217579",
         "key": "ART-4069",
         "fields": {"summary": "Verification \\"C\\""}
      },
            {
         "expand": "operations,versionedRepresentations",
         "id": "217577",
         "self": "issue/217577",
         "key": "ART-4068",
         "fields": {"summary": "#[ART] Enum type"}
      }
   ]
}
'''
File csvFile = new File( 'C:/temp/all1.csv')

def jsonSlurper = new JsonSlurper()
def config = [ // header -> extractor
    "key": { it.key },
    "summary": { it.fields.summary }
]

def encode(e) { // help with nulls; quote the separator
    (e ?: "").replaceAll(";", "\\;")  
}

def csvLine(items) { // write items as "CSV"
  println(items.collect{ encode it }.join(";"))
}

def obj = new JsonSlurper().parseText(json)
csvLine(config.keySet())
obj.issues.each{ issue ->
    csvLine(config.values().collect{ f -> f issue })
}
结果:
钥匙摘要
ART-4070#[第3条]前验证“S”
第4069条;验证“C”

第4068条#[ART]Enum type

要使用当前代码,可以在
csvLine
函数,根据实际数据量,这可能会 在性能和资源之间达成良好的折衷

或者您可以一次编写整个CSV。例如

// prepare whole table
def data = [config.keySet()]
data.addAll(
    obj.issues.collect{ issue ->
        config.values().collect{ f -> f issue }
    }
)
// write table as csv
def csvFile = "/tmp/out.csv" as File
csvFile.text = data.collect{
    it.collect{ encode it }.join(";")9
}.join("\n")

def csvLine(items){//将项写为“CSV”csvFile.append((items.collect{encode it}.join(;“”))吗?没有这样的属性:类的csvFile