Json vs代码运行c代码
我有一个使用makefile构建的现有代码库,我想使用VisualStudio代码来运行它。 有my launch.json和tasks.jsonJson vs代码运行c代码,json,visual-studio-code,Json,Visual Studio Code,我有一个使用makefile构建的现有代码库,我想使用VisualStudio代码来运行它。 有my launch.json和tasks.json { "version": "0.2.0", "configurations": [{ "name": "C Launch (GDB)", "type": "cppdbg", "request": "launch", "launchOptionType": "Local", "targetArchitect
{
"version": "0.2.0",
"configurations": [{
"name": "C Launch (GDB)",
"type": "cppdbg",
"request": "launch",
"launchOptionType": "Local",
"targetArchitecture": "x64",
"cwd": "${workspaceRoot}",
"program": "E:/code/c",
"miDebuggerPath": "E:/Program Files/TDM-GCC-64/bin/gdb64.exe",
"args": [""],
"stopAtEntry": false,
"externalConsole": true,
"preLaunchTask": "gcc"
}]
}
{
"version": "0.1.0",
"command": "gcc",
"args": ["${file}", "-o", "${fileBasenameNoExtension}.exe", "-g3", "-Og", "-Wall", "-static-libgcc", "-std=c11", "-fexec-charset=GBK", "-finput-charset=UTF-8"],
"showOutput": "always",
"problemMatcher": {
"owner": "c",
"fileLocation": ["relative", "${workspaceRoot}"],
"pattern": {
"regexp": "^(.*):(\\d+):(\\d+):\\s+(warning|error):\\s+(.*)$",
"file": 1,
"line": 2,
"column": 3,
"severity": 4,
"message": 5
}
}
}
然后当我运行Hello world
时,就会出现一些问题
尝试更改路径以在Windows上使用
\
而不是/
。由于必须在json字符串中转义\
,因此实际值为:
"program": "E:\\code\\c\\${fileBasenameNoExtension}.exe"
假设生成的可执行文件实际位于
E:\code\c
我得到了它。但问题似乎仍然存在。launch:program'E:\code\c'不存在
如果查看磁盘,该路径是否有可执行文件?如果添加.exe
,使其值为:“E:\\code\\c.exe”
,该怎么办?