有没有办法使用Julia'；s readdir（）？

我有上千个文件名为

LOGS\u A1

，

LOGS\u A2

，LOGS\u A3

，…，

LOGS\u A16281`，我想按顺序列出这些文件

cwd = pwd()
ParentDir = joinpath(cwd,"LOGS_A")
dirs = readdir(ParentDir, join=true, sort=true)

但是，它按字母顺序排列条目：

LOGS_A999
LOGS_A9990
LOGS_A9991
LOGS_A9992
LOGS_A9993
LOGS_A9994
LOGS_A9995
LOGS_A9996
LOGS_A9997
LOGS_A9998
LOGS_A9999

有没有办法将其排序，使其从1到16281列出？

这是您想要的吗

julia> src = ["LOGS_A1",
              "LOGS_A10",
              "LOGS_A11",
              "LOGS_A2",
              "LOGS_A3",
              "LOGS_A4",
              "LOGS_A5",
              "LOGS_A6",
              "LOGS_A7",
              "LOGS_A8",
              "LOGS_A9"];

julia> sort(src, by = x -> parse(Int, chop(x, head=6, tail=0)))
11-element Array{String,1}:
 "LOGS_A1"
 "LOGS_A2"
 "LOGS_A3"
 "LOGS_A4"
 "LOGS_A5"
 "LOGS_A6"
 "LOGS_A7"
 "LOGS_A8"
 "LOGS_A9"
 "LOGS_A10"
 "LOGS_A11"

我使用了

chop

，因为在这种情况下，它看起来很简单，因为我知道你的前缀到处都是一样的

另一种选择是：

julia> src[sortperm(parse.(Int, chop.(src, head=6, tail=0)))]
11-element Array{String,1}:
 "LOGS_A1"
 "LOGS_A2"
 "LOGS_A3"
 "LOGS_A4"
 "LOGS_A5"
 "LOGS_A6"
 "LOGS_A7"
 "LOGS_A8"
 "LOGS_A9"
 "LOGS_A10"
 "LOGS_A11"

---

速度稍快，但编写起来更复杂（在您的用例中，速度可能并不重要）。

要获得更简单、更可靠的答案，请使用：

julia> using Pkg; pkg"add NaturalSort"
  Resolving package versions...
Updating `~/.julia/environments/v1.5/Project.toml`
  [c020b1a1] + NaturalSort v1.0.0
Updating `~/.julia/environments/v1.5/Manifest.toml`
  [c020b1a1] + NaturalSort v1.0.0

julia> using NaturalSort
[ Info: Precompiling NaturalSort [c020b1a1-e9b0-503a-9c33-f039bfc54a85]

julia> src = ["LOGS_A1","LOGS_A10","LOGS_A11","LOGS_A2","LOGS_A3","LOGS_A4",
              "LOGS_A5","LOGS_A6","LOGS_A7","LOGS_A8","LOGS_A9"];

julia> sort(src, lt=natural)
11-element Array{String,1}:
 "LOGS_A1"
 "LOGS_A2"
 "LOGS_A3"
 "LOGS_A4"
 "LOGS_A5"
 "LOGS_A6"
 "LOGS_A7"
 "LOGS_A8"
 "LOGS_A9"
 "LOGS_A10"
 "LOGS_A11"