Julia 如何将值放入结构的子记录中？

如果需要在Julia中的子结构中输入值，怎么可能？ 例如，我有这个结构

struct individual
    position
    cost
end

pop = [individual(rand(0:1,10),[]) for i in 1:2]

如果位置将在代码中更改为此值

x=[0,2,0,0,2,0,0,2,2]

怎么可能呢

如果追加！（）被使用

但是我想要这个

individual([0, 2, 0, 0, 2, 0, 0, 2, 2, 2], Any[])

---

你能帮帮我吗。非常感谢

请在添加

x

之前清空容器，如下所示：

append!(empty!(pop[1].position), x)

julia> mutable struct individual
           position
           cost
       end

julia> pop = [individual(rand(0:1,10),[]) for i in 1:2]
2-element Array{individual,1}:
 individual([1, 1, 1, 1, 0, 0, 0, 0, 0, 1], Any[])
 individual([0, 0, 0, 1, 0, 1, 1, 1, 1, 1], Any[])

julia> x=[0, 2, 0, 0, 2, 0, 0, 2, 2, 2]
10-element Array{Int64,1}:
 0
 2
 0
 0
 2
 0
 0
 2
 2
 2

julia> pop[1].position = x
10-element Array{Int64,1}:
 0
 2
 0
 0
 2
 0
 0
 2
 2
 2

julia> pop
2-element Array{individual,1}:
 individual([0, 2, 0, 0, 2, 0, 0, 2, 2, 2], Any[])
 individual([0, 0, 0, 1, 0, 1, 1, 1, 1, 1], Any[])

或者将

individual

定义为可变的，然后您可以像这样简单地使用赋值：

append!(empty!(pop[1].position), x)

julia> mutable struct individual
           position
           cost
       end

julia> pop = [individual(rand(0:1,10),[]) for i in 1:2]
2-element Array{individual,1}:
 individual([1, 1, 1, 1, 0, 0, 0, 0, 0, 1], Any[])
 individual([0, 0, 0, 1, 0, 1, 1, 1, 1, 1], Any[])

julia> x=[0, 2, 0, 0, 2, 0, 0, 2, 2, 2]
10-element Array{Int64,1}:
 0
 2
 0
 0
 2
 0
 0
 2
 2
 2

julia> pop[1].position = x
10-element Array{Int64,1}:
 0
 2
 0
 0
 2
 0
 0
 2
 2
 2

julia> pop
2-element Array{individual,1}:
 individual([0, 2, 0, 0, 2, 0, 0, 2, 2, 2], Any[])
 individual([0, 0, 0, 1, 0, 1, 1, 1, 1, 1], Any[])