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Karate 空手道中两个数组的一对一映射_Karate - Fatal编程技术网

Karate 空手道中两个数组的一对一映射

Karate 空手道中两个数组的一对一映射,karate,Karate,因此,最终映射结果应该是 * def alphabets = ["a","b","c"] * def number = ["1","2","3"] 尝试此数组reduce功能。它应该给出预期的结果 final =[{"a":"1"},{"b":2""},{"c":"3

因此,最终映射结果应该是

* def alphabets = ["a","b","c"]
* def number = ["1","2","3"]

尝试此数组
reduce
功能。它应该给出预期的结果

final =[{"a":"1"},{"b":2""},{"c":"3"}]

尝试此数组
reduce
功能。它应该给出预期的结果

final =[{"a":"1"},{"b":2""},{"c":"3"}]
var字母表=[“a”、“b”、“c”]
变量编号=[“1”、“2”、“3”]
res=alphabets.map((e,i)=>({[e]:number[i]}))
console.log(res)
var字母表=[“a”、“b”、“c”]
变量编号=[“1”、“2”、“3”]
res=alphabets.map((e,i)=>({[e]:number[i]}))

console.log(res)
给你。下次也许你不应该把你的问题标记为JS/JSON;)


给你。下次也许你不应该把你的问题标记为JS/JSON;)


这回答了你的问题吗?这回答了你的问题吗?
* def fun = function(x, i){ var pair = {}; pair[x] = number[i]; return pair }
* def pairs = karate.map(alphabets, fun)