Karate 无法使用没有标识符名称的数组断言单个数组中的所有元素

答复：

[
  {
    id: "1",
    modelId: "301",
    modelName: "x",
    trimId: "301",
    trimName: "up!",
    derivativeName: "xx",
    fuelType: "PETROL",
    tco: {
      price: {
        tco: null,
        retail: 12,
        offer: null,
        subsidy: null,
        residual: null
      },
      milesPerYear: 10000,
      mpg: 51.5,
      fuelCost: 1.1,
      milesPerKW: 0,
      monthsOfOwnership: 48,
      energyCost: 12,
      tax: 42,
      comparable: false
    }
  },
  {
    id: "1239",
    modelId: "301",
    modelName: "up!",
    trimId: "301",
    trimName: "x",
    derivativeName: "xx",
    fuelType: "PETROL",
    tco: {
      price: {
        tco: null,
        retail: 1,
        offer: null,
        subsidy: null,
        residual: null
      },
      milesPerYear: 10000,
      mpg: 53.2,
      fuelCost: 1.1,
      milesPerKW: 0,
      monthsOfOwnership: 48,
      energyCost: 12,
      tax: 4,
      comparable: false
    }
  }
]

我试图检查钥匙

燃油类型

=汽油时，钥匙

燃油成本

必须等于1.1

我试过以下方法

* def isValid = function(x) { return response[0].fuelType == "PETROL" &&      response[0].tco.fuelCost == 1.1} 
* match each response === '#? isValid(_)'

^^但这只是断言顶层元素

我尝试了以下方法：

* def isValid = function(x) { return response[*].fuelType == "PETROL" &&      response[*].tco.fuelCost == 1.1} * match each response === '#? isValid(_)'
* match each response === '#? isValid(_)'

^^但这会抛出一个操作数错误

---

在一个没有标识符名称的数组中，我有大约260个元素，我需要在所有260个元素中为``fuelType==“Petrole”&fuelCost==1.1断言这两行非常有效：

* def isValid = function(x) { return x.fuelType == "PETROL" && x.tco.fuelCost == 1.1 } 
* match each response == '#? isValid(_)'

---

你用了一个三重等式，这是错误的。阅读文档：

我尽量简短，但显然不起作用。我补充了另一个，谢谢，太好了，一个“简单的例子”的全部要点都没有了。不管怎样，看看我的答案