Linux 对文件进行计数，如果计数大于给定的限制，则删除剩余的文件

我使用下面的脚本递归地计算目录中的文件数。在每个子目录中，如果计数大于3，我需要删除剩余的文件

是否需要为每个子目录添加另一个for循环，如果超过3个，则删除其余文件

START=$HOME

# change your directory to command line if passed
# otherwise use home directory
[ $# -eq 1 ] && START=$1 || :

if [ ! -d $START ]
then
        echo "$START not a directory!"
        exit 1
fi

# use find command to get all subdirs name in DIRS variable
DIRS=$(find "$START" -type d)

# loop thought each dir to get the number of files in each of subdir
for d in $DIRS
do
   [ "$d" != "." -a "$d" != ".." ] &&  echo "$d dirctory has $(ls -l $d | wc -l) files" || :

done

---

find

已经提供了

START

下面的子目录数。由于包含

PWD

（

），计数增加了

1

。因此，要获得

START

下面的子目录数，不包括

START

本身：

find "$START" -type d | echo "subdirs: $(($(wc -l)-1))"

输出示例：

subdirs: 6

files: 128

$ bash del3dirs.sh

processing: /home/david/scr/tmp/stack/sav

num files: 5
  keeping : /home/david/scr/tmp/stack/sav/dna.sh
  keeping : /home/david/scr/tmp/stack/sav/dict-sort_1.sh
  keeping : /home/david/scr/tmp/stack/sav/_20140702-211202.tar.xz
  deleting: /home/david/scr/tmp/stack/sav/dict-sort.sh
  deleting: /home/david/scr/tmp/stack/sav/dict-sort_2.sh

processing: /home/david/scr/tmp/stack/tmp

num files: 13
  keeping : /home/david/scr/tmp/stack/tmp/File1950text.doc
  keeping : /home/david/scr/tmp/stack/tmp/vcs1dump
  keeping : /home/david/scr/tmp/stack/tmp/File2014text.xls
  deleting: /home/david/scr/tmp/stack/tmp/File307list.cvs
  deleting: /home/david/scr/tmp/stack/tmp/vcsa1dump
  (snip)

processing: /home/david/scr/tmp/stack/tmp/a

num files: 2
  keeping : /home/david/scr/tmp/stack/tmp/a/b/b.txt
  keeping : /home/david/scr/tmp/stack/tmp/a/b/b.txt.bac

processing: /home/david/scr/tmp/stack/dat

num files: 68
  keeping : /home/david/scr/tmp/stack/dat/outlier.dat
  keeping : /home/david/scr/tmp/stack/dat/3line.dat.sav
  keeping : /home/david/scr/tmp/stack/dat/f1f2.dat
  deleting: /home/david/scr/tmp/stack/dat/datb.dat
  deleting: /home/david/scr/tmp/stack/dat/lline.dat
  deleting: /home/david/scr/tmp/stack/dat/vowels.txt

要获取文件数，只需使用

-type f

（无需减去1）：

输出示例：

subdirs: 6

files: 128

$ bash del3dirs.sh

processing: /home/david/scr/tmp/stack/sav

num files: 5
  keeping : /home/david/scr/tmp/stack/sav/dna.sh
  keeping : /home/david/scr/tmp/stack/sav/dict-sort_1.sh
  keeping : /home/david/scr/tmp/stack/sav/_20140702-211202.tar.xz
  deleting: /home/david/scr/tmp/stack/sav/dict-sort.sh
  deleting: /home/david/scr/tmp/stack/sav/dict-sort_2.sh

processing: /home/david/scr/tmp/stack/tmp

num files: 13
  keeping : /home/david/scr/tmp/stack/tmp/File1950text.doc
  keeping : /home/david/scr/tmp/stack/tmp/vcs1dump
  keeping : /home/david/scr/tmp/stack/tmp/File2014text.xls
  deleting: /home/david/scr/tmp/stack/tmp/File307list.cvs
  deleting: /home/david/scr/tmp/stack/tmp/vcsa1dump
  (snip)

processing: /home/david/scr/tmp/stack/tmp/a

num files: 2
  keeping : /home/david/scr/tmp/stack/tmp/a/b/b.txt
  keeping : /home/david/scr/tmp/stack/tmp/a/b/b.txt.bac

processing: /home/david/scr/tmp/stack/dat

num files: 68
  keeping : /home/david/scr/tmp/stack/dat/outlier.dat
  keeping : /home/david/scr/tmp/stack/dat/3line.dat.sav
  keeping : /home/david/scr/tmp/stack/dat/f1f2.dat
  deleting: /home/david/scr/tmp/stack/dat/datb.dat
  deleting: /home/david/scr/tmp/stack/dat/lline.dat
  deleting: /home/david/scr/tmp/stack/dat/vowels.txt

您可以将这一切放在一起，同时将

查找

文件的

-maxdepth

限制为

1

，并完成所需的操作注意：下面的脚本只打印它是将

保留

还是

删除

文件（保留每个目录中的前3个，删除其余的）。您需要实施自己的方案，保留/删除该方案以满足您的需要。这将让您了解您可以做什么：

#!/bin/bash

start="${1:-$PWD}"

[ -d "$start" ] || {
    printf "error: directory not accessible '%s'\n", "$start"
    exit 1;
}

declare -a files                                # declare an array to hold files

for i in $(find "$start" -type d); do           # find all subdirs

    [ "$i" = "$PWD" ] && continue               # skip the current (top) dir

    printf "\nprocessing: %s\n\n" "$i"          # simple dir info output (not needed)

    files=( $(find "$i" -maxdepth 1 -type f) )  # fill array w/files in each dir (no subs)
    if [ "${#files[@]}" -gt 0 ]; then           # if subdir has files
        echo "num files: ${#files[@]}"          # No. of files in dir info (not needed)
        for ((j=0; j<${#files[@]}; j++)); do    # for each file
            if [ "$j" -lt 3 ]; then             # if first 3, keep
                printf "  keeping : %s\n" "${files[j]}"
            else                                # files 4+ delete
                printf "  deleting: %s\n" "${files[j]}"
            fi
        done
    fi
done

---

感谢您的回答，我的目的是统计每个子目录中的文件数量，如果数量超过“3”，则删除剩余的文件。有可能吗？好的，给我一秒钟，我会帮你修改答案。非常感谢我正在检查：）效果很好，谢谢！！如果名称类似于“test（copy）.txt”，则有一个条件除外。然后将其作为两个文件。您必须详细说明（张贴示例）。在

“test（copy）.txt”

上不应进行扩展或分词。我来测试一下。哦，这些看起来不像普通的文件名字符。Bash抱怨说，除非对paren进行转义，否则会使用paren创建文件名。让我看看是否有快速解决办法。您使用的是什么操作系统？刚刚测试过，它在这里工作得很好：

删除：/home/david/scr/tmp/stack/dat/tmp/b/text（copy）.txt