Linux 如果在csv文件中找到匹配项，如何获取整个记录

如果找到匹配项，我想从csv文件中获取记录

样本数据：

当我grep一个像A1这样的关键字时，所有作为A1的记录都应该显示为输出

输出：

我的命令不起作用：

试试这个

$ egrep "A1|NAME" demo.csv 
"ID","NAME","CITY"
"001","A1","B1"
"001","A1","B1"
"001","A1","B1"
"001","A1","B1"

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对于您的问题，请检查上的答案

上面的链接可能会有所帮助

除此之外，我还使用

我通过迭代excel工作表获取了行，Panda也可以使用CSV

我使用了以下代码：

df1 = pd.read_excel('Path of xlsx') #   

df = pd.DataFrame(df1, columns= [<Name of Columns>])

pd.DataFrame(df1,columns['From','To'])

for i in range(len(df)): 
from_postal_code = df.loc[i, "From"]
to_postal_code = df.loc[i, "To"]
print(from_postal_code)
print(to_postal_code)

希望这有帮助

使用csvgrep始终是一个好主意，在可能的情况下，使用能够理解结构化格式而不是通用格式的工具：

$ csvgrep -c 2 -m A1 demo.csv
ID,NAME,CITY
001,A1,B1
001,A1,B1
001,A1,B1
001,A1,B1

$ egrep "A1|NAME" demo.csv 
"ID","NAME","CITY"
"001","A1","B1"
"001","A1","B1"
"001","A1","B1"
"001","A1","B1"

df1 = pd.read_excel('Path of xlsx') #   

df = pd.DataFrame(df1, columns= [<Name of Columns>])

pd.DataFrame(df1,columns['From','To'])

for i in range(len(df)): 
from_postal_code = df.loc[i, "From"]
to_postal_code = df.loc[i, "To"]
print(from_postal_code)
print(to_postal_code)

$ csvgrep -c 2 -m A1 demo.csv
ID,NAME,CITY
001,A1,B1
001,A1,B1
001,A1,B1
001,A1,B1