Listview 从串行端口向列表视图添加项目时出错。。
我正在读取串行端口以读取gsm调制解调器中的消息,然后在列表视图中显示它们。但我最终得到了一个包含冗余项的列表视图。我无法理解为什么会发生这种事Listview 从串行端口向列表视图添加项目时出错。。,listview,serial-port,modem,Listview,Serial Port,Modem,我正在读取串行端口以读取gsm调制解调器中的消息,然后在列表视图中显示它们。但我最终得到了一个包含冗余项的列表视图。我无法理解为什么会发生这种事 { port.DiscardOutBuffer(); port.DiscardInBuffer(); string res; Thread.Sleep(5000); res = port.ReadExisting(); ShortMessageCollect
{
port.DiscardOutBuffer();
port.DiscardInBuffer();
string res;
Thread.Sleep(5000);
res = port.ReadExisting();
ShortMessageCollection messages = new ShortMessageCollection();
Regex r = new Regex(@"\+CMGL: (\d+),""(.+)"",""(.+)"",(.*),""(.+)""\r\n(.+)\r\n");
Match m = r.Match(res);
while (m.Success)
{
ShortMessage msg = new ShortMessage();
msg.Index = m.Groups[1].Value;
msg.Status = m.Groups[2].Value;
msg.Sender = m.Groups[3].Value;
msg.Alphabet = m.Groups[4].Value;
msg.Sent = m.Groups[5].Value;
msg.Message = m.Groups[6].Value;
messages.Add(msg);
m = m.NextMatch();
objShortMessageCollection = (ShortMessageCollection)messages;
foreach (ShortMessage mesg in objShortMessageCollection)
{
ListViewItem item = new ListViewItem(new string[] {mesg.Index, mesg.Sender, mesg.Message, mesg.Sent});
item.Tag = mesg;
lvwMessages.Items.Insert(0, item);
}
}
使用以下代码删除冗余:
lvwMessages.Sorting = SortOrder.Descending;
int i = 0;
while (i < lvwMessages.Items.Count - 1)
{
if (lvwMessages.Items[i].Tag == lvwMessages.Items[i + 1].Tag)
lvwMessages.Items[i + 1].Remove();
else
i++;
}
lvwMessages.Sorting=SortOrder.Descending;
int i=0;
而(i