Loops python中if语句的while循环

我正在制作一个小程序，是python的新手，因此有一点理解上的问题，需要知道我的错误，当用户输入了正确的选择（如1、2或3）时，它应该进入循环并运行if语句。一旦完成，它应该退出。但显然，这并不完美

print ("Selection of the mode\n Easy \n Moderate \n tough")
selection = int(input("Please enter the right Choice!! > "))

while selection != '':
    if selection == 1:
        print("\ngoodluck")
    elif selection == 2:
        print('\nyou are brave')
    elif selection == 3:
        print ('\nyou must be kidding')
    selection = int(input("Please enter the right Choice!!! > "))

我现在正在执行此操作，但已完成所有if语句，但我只想在if语句的第一个选择正确后退出。

尝试此操作

print ("Selection of the mode\n Easy \n Moderate \n tough")
selection = input("Please enter the right Choice!! > ")

while selection != '':
    if selection == '1':
        print("\ngoodluck")
        break
    elif selection == '2':
        print('\nyou are brave')
        break
    elif selection == '3':
        print ('\nyou must be kidding')
        break
    selection = input("Please enter the right Choice!!! > ")

此外，不需要多次使用

input（）

print ("Selection of the mode\n Easy \n Moderate \n tough")
selection = int(input("Please enter the right Choice!! > "))

while selection != '':
    if selection == 1:
        print("\ngoodluck")
        break
    elif selection == 2:
        print('\nyou are brave')
        break
    elif selection == 3:
        print ('\nyou must be kidding')
        break
    selection = input("Please enter the right Choice!!! > ")

---

您需要在所有打印函数之后添加

break

。@AvinashRaj没有这样做：/

break

语句应该像AvinashRaj说的那样工作。@Kutttayqaratera您是说，如果输入1，它不会退出吗？好的@itzmeontv，下面的答案是正确的，但是当键入1、2或3时，while循环仍然没有退出，它仍然在重复出现。

print ("Selection of the mode\n Easy \n Moderate \n tough")
while True:
    selection = int(input("Please enter the right Choice!!! > "))
    if selection == 1:
        print("\ngoodluck")
        break
    elif selection == 2:
        print('\nyou are brave')
        break
    elif selection == 3:
        print ('\nyou must be kidding')
        break