Lua string.gsub在string.gmatch中？

我创建了这个简单的示例脚本来输出食物列表。如果食物是水果，那么水果的颜色也会显示出来。我面临的问题是如何处理“草莓”的不规则多元化

fruits = {apple = "green", orange = "orange", stawberry = "red"}
foods = {"potatoes", "apples", "strawberries", "carrots", "crab-apples"}

for _, food in ipairs(foods) do
    for fruit, fruit_colour in pairs(fruits) do
        duplicate = false
        if (string.match(food, "^"..fruit) or string.match((string.gsub(food, "ies", "y")), "^"..fruit)) and not(duplicate) then -- this is where the troubles is!
            print(food.." = "..fruit_colour)
            duplicate = true
            break
        end
    end
    if not(duplicate) then
        print(food)
    end
end

现在程序输出：

potatoes
apples = green
strawberries
carrots
crab-apples

我想要的是：

potatoes
apples = green
strawberries = red
carrots
crab-apples

---

我不明白为什么这不能像我希望的那样工作

stawberry

应该是

草莓

。循环将

草莓

更改为

草莓

，然后尝试将

草莓

与

^stawberry

匹配，但键入错误导致其不匹配。

首先，您在此处遗漏了草莓的拼写：

fruits = {apple = "green", orange = "orange", stawberry = "red"}

还可以将lua表作为集合使用，这意味着不需要嵌套循环搜索重复项。它可以简化为：

fruits = {apple = "green", orange = "orange", strawberry = "red"}
foods = {"potatoes", "apples", "strawberries", "carrots", "crab-apples"}

function singular(word)
    return word:gsub("(%a+)ies$", "%1y"):gsub("(%a+)s$", "%1")
end

for _, food in ipairs(foods) do
    local single_fruit = singular(food)
    if fruits[single_fruit] then
        print(food .. " = " .. fruits[single_fruit])
    else
        print(food)
    end
end

---

很高兴，我犯了那个愚蠢的错误，因为我现在知道了集合！非常感谢你！