如何在Matlab中用求中心点绘制正方形？

我想画几个由中心点定义的正方形。这是我目前的代码：

x1=0;
x2=1;
y1=0;
y2=1;
x = [x1, x2, x2, x1, x1];
y = [y1, y1, y2, y2, y1];
plot(x, y, 'b-', 'LineWidth', 3);
hold on;
x1=0.25;
x2=.75;
y1=0.25;
y2=.75;
x = [x1, x2, x2, x1, x1];
y = [y1, y1, y2, y2, y1];
plot(x, y, 'b-');
xlim([-1, 2]);
ylim([-1, 2]);

我想在以下表格中使用：

points  = [1,4];
lengthSquare = 5;
square(points, lengthSquare);

---

这样的办法应该行得通。这是基于我之前的回答

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如何填充正方形？如果您想填充，请使用

fill

或

patch

而不是

plot

。我在

square

函数中对这两个参数进行了treid，但显示：输入参数不够。我对答案进行了更改，但您不应该回来说“它不起作用”您应该查看文档（只需在遇到问题的函数上点击F1）

function square( centers, sides )
h = figure(47);
close(h)
h = figure(47);

nSides = 4; % number of sides of regular polygon
rot = 0;    % rotation angle in degrees

% every polygon has the same side length?
if length(sides) == 1
    sides = sides * ones(size(centers, 1),1);
end

x0 = centers(:,1);
y0 = centers(:,2);

filledShape = true;

[x, y] = arrayfun(@(X0, Y0, S) vertexCoords(X0, Y0, S, nSides, ~filledShape, rot), x0,y0,sides, 'uni', 0);

if filledShape
    for i = 1:length(x)
        patch('Faces', 1:length(x{i}), 'Vertices', [x{i}, y{i}],'FaceColor','red')
    end

else
    T = [x, y]';
    plot(T{:},'LineWidth',2)
end

axis equal

end

function [x, y] = vertexCoords(x0, y0, s, nSides, rot, closed)
        %Need nSides+1 to close the figure.
        theta = linspace(0, 2*pi, nSides+1)' - (pi/nSides) - rot;

    if ~closed
        theta(end) = [];
    end

    % convert from side length to diameter
    D = 2*s ./ sqrt(2 - 2*cos(2*pi/nSides));

        %Convert from polar to Cartesian coordinates 
        x = D/2 * cos(theta) + x0;
        y = D/2 * sin(theta) + y0;
end