没有通过字节字符串单步执行足够的MIPS

我有一个赋值，在这里我必须输入一个十进制数，并输出二进制版本中有多少个“1”位。该数字不能大于或等于4096，因此需要进行错误检查。我们还必须使用至少一个逻辑运算符。我已经把所有这些东西都设置好了，但我似乎无法让它们正常工作

我的问题是： 循环似乎没有通过第8位。数字4095应该返回11时返回8，2048返回0。任何最大为255的输入都会返回正确的值

事实上，我已经从这个网站上以前的帖子中得到了一些想法，这就是我所能做到的。如有更多帮助，我们将不胜感激

.data
inputStr: .asciiz "\nEnter a positive integer from 0-4095: "
errorStr: .asciiz "The input was not in the specified range..."
resultStr: .asciiz "The number of '1' bits: "
newline: .asciiz "\n"
.text

main:

addi $s0, $zero, 4096       #Created a variable to be used for error checking.

############Print inputStr calling for the integer.
li $v0, 4
la $a0, inputStr        
syscall

############Store input as $a1. 
li $v0, 5
syscall
addu $a1, $zero, $v0

############Check to see if input is valid.
bge $v0, $s0, PrintError    #End if input >= 4096

############Print a blank line.
addi $v0, $zero, 4
la $a0, newline
syscall

############Call Bits procedure.
j Bits              #Not a jal because Bits takes over from here basically.

############Prints the result of running Bits procedure. (How many 1's)
End:
addi $v0, $zero, 4
la $a0, resultStr
syscall

addi $v0, $zero, 1
add $a0, $zero, $v1
syscall

addi $v0, $zero, 4
la $a0, newline

addi $v0, $zero, 10
syscall

############Tells the user there was an error with their input and ends program.
PrintError:
addi $v0, $zero, 4
la $a0, errorStr
syscall

addi $v0, $zero, 10
syscall

############Bits procedure.         
#This procedure uses:
#$t1 as a loop parser
#$v1 as a return variable

Bits:
move $t0, $a1
sll $t0, $t0, 24
add $t5, $zero, $zero

Loop:
beq $t5, 13, End        #Case to end loop
slt $t1, $t0, $zero
andi $t2, $t1, 1        #Ands $t1 with 1
beq $t2, 1, addOne      #If $t2 still equals 1, addOne
addi $t5, $t5, 1        #Increase parser by 1
sll $t0, $t0, 1
j Loop              #Repeat

addOne:             #Adds 1 to the output counter
addi $v1, $v1, 1        #Increment output counter
addi $t5, $t5, 1        #Increase parser by 1
sll $t0, $t0, 1 
j Loop              #Repeat

---

没关系，我修好了。我所做的只是在Bits过程中将sll命令随机切换为移位20，而不是24。我不知道为什么会这样，如果有人能插话，我会非常感激。可能是因为log24096是12，32-12==20。