如何在mongodbmo中建立多对多关系
我刚刚开始学习MongoDB。 有人能介绍一下如何用mongodb实现这个例子吗 榜样如何在mongodbmo中建立多对多关系,mongodb,Mongodb,我刚刚开始学习MongoDB。 有人能介绍一下如何用mongodb实现这个例子吗 榜样 # Here are my categories > hmset category:1 name cinema ... more fields ... > hmset category:2 name music ... more fields ... > hmset category:3 name sports ... more fields ... > hmset categ
# Here are my categories
> hmset category:1 name cinema ... more fields ...
> hmset category:2 name music ... more fields ...
> hmset category:3 name sports ... more fields ...
> hmset category:4 name nature ... more fields ...
# Here are my users
> hmset user:1 name Jack ... more fields ...
> hmset user:2 name John ... more fields ...
> hmset user:3 name Julia ... more fields ...
# Let's establish the many-to-many relationship
# Jack likes cinema and sports
# John likes music and nature
# Julia likes cinema, music and nature
# For each category, we keep a set of reference on the users
> sadd category:1:users 1 3
> sadd category:2:users 2 3
> sadd category:3:users 1
> sadd category:4:users 2 3
# For each user, we keep a set of reference on the categories
> sadd user:1:categories 1 3
> sadd user:2:categories 2 4
> sadd user:3:categories 1 2 4
在MongoDB中,您可以选择预加入数据,因此可以将文档放在以下位置:
user : "John",
categories : ["music", "nature"]
还有一个放置引用的选项(更像RDBMS):
这基本上取决于您的数据访问模式。因此,如果您基本上只检索与用户相关的类别,那么第一种情况应该是好的,否则,您可以考虑第二种情况,对用户和类别有不同的集合,然后引用它们,它们会出现如下情况,例如:
var category = { _id: "music"
, name: "Musical Category"
, users: ["jack", "julia", "john"] }
var user = { _id: "jack", name: "Jack", categories: ["music"]}
db.categories.save(category)
db.users.save(user)
db.categories.find({_id: {$in: user.categories}}) // categories for user
db.users.find({_id: {$in: category.users}}) // users for category
但我刚刚谈到了模式设计的主题。您必须分析基数和数据访问模式,以获得可靠的设计。
以下来自Mongo的帖子给出了很好的解释,并举例说明:
从手册中:谢谢!那很有趣
var category = { _id: "music"
, name: "Musical Category"
, users: ["jack", "julia", "john"] }
var user = { _id: "jack", name: "Jack", categories: ["music"]}
db.categories.save(category)
db.users.save(user)
db.categories.find({_id: {$in: user.categories}}) // categories for user
db.users.find({_id: {$in: category.users}}) // users for category