Mongodb-在重复记录上追加

我正试图使用mongodb在Java中完成这项任务。假设我有一份员工名单（名字、姓氏、电话号码）。现在，一些员工可以有多个电话号码

假设我有一个员工列表（我正在解析一个xml文档）：

我尝试的是首先解析文档并插入firstname和lastname。然后，查询firstname和lastname（如果存在），使用$push追加电话号码来更新记录：

File fXmlFile = new File("contacts.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder;
Document doc;

try {

MongoClient mongo = new MongoClient("localhost", 27017);
DB db = mongo.getDB("testdb");
dBuilder = dbFactory.newDocumentBuilder();
DBCollection table = db.getCollection("employees");

doc = dBuilder.parse(fXmlFile);
doc.getDocumentElement().normalize();
NodeList nList = doc.getElementsByTagName("contact");

for (int temp = 0; temp < nList.getLength(); temp++) {

  Node nNode = nList.item(temp);
  BasicDBObject document = new BasicDBObject();

  if (nNode.getNodeType() == Node.ELEMENT_NODE) {

    Element eElement = (Element) nNode;

    String firstName = eElement.getElementsByTagName("name").item(0).getTextContent();
    String lastName =eElement.getElementsByTagName("lastName").item(0).getTextContent();

    document.put("name", firstName);
    document.put("lastName", lastName);
    table.insert(document);

    String phoneNumber = eElement.getElementsByTagName("phone").item(0).getTextContent();
    BasicDBObject query = new BasicDBObject();
    query.put("name", firstName);
    query.put("lastName", lastName);

    BasicDBObject push = new BasicDBObject();
    push.put("$push", new BasicDBObject("phone",phoneNumber));
    table.update(query, push);
}

所以基本上，有一张约翰·史密斯的唱片，没有添加电话号码，为什么？为什么我的前两条记录显示为lastname first

我是mongodb的新手，所以这是一段非常草率和快速的代码，只是为了看看如何完成这项任务

我将非常感谢任何帮助

---

谢谢。

Mongodb的概念是（如果不存在则插入，如果存在则更新）

尝试使用：将upsert标志设置为true

大概是这样的：

{ "_id" : ObjectId("5297a3d84a9cb457a3f33b23"), "name" : "John", "lastName" : "Smith", "phone" : [  "555 123 23 23",  "555 666 66 66 23" ] }
{ "_id" : ObjectId("5297a3d84a9cb457a3f33b24"), "name" : "Jane", "lastName" : "Doe", "phone" : [  "555 123 44 44" ] }

---

收藏。更新（新BasicDBObject（“姓名”、“约翰”）。追加（“姓氏”、“史密斯”）、新BasicDBObject（“推送”）、新BasicDBObject（“电话”、“新号码”）、真、假）

哇，我的生活不必要地复杂化了。我知道upsert命令，但只是不知道如何正确地执行：-）谢谢你，它工作起来很有魅力！

File fXmlFile = new File("contacts.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder;
Document doc;

try {

MongoClient mongo = new MongoClient("localhost", 27017);
DB db = mongo.getDB("testdb");
dBuilder = dbFactory.newDocumentBuilder();
DBCollection table = db.getCollection("employees");

doc = dBuilder.parse(fXmlFile);
doc.getDocumentElement().normalize();
NodeList nList = doc.getElementsByTagName("contact");

for (int temp = 0; temp < nList.getLength(); temp++) {

  Node nNode = nList.item(temp);
  BasicDBObject document = new BasicDBObject();

  if (nNode.getNodeType() == Node.ELEMENT_NODE) {

    Element eElement = (Element) nNode;

    String firstName = eElement.getElementsByTagName("name").item(0).getTextContent();
    String lastName =eElement.getElementsByTagName("lastName").item(0).getTextContent();

    document.put("name", firstName);
    document.put("lastName", lastName);
    table.insert(document);

    String phoneNumber = eElement.getElementsByTagName("phone").item(0).getTextContent();
    BasicDBObject query = new BasicDBObject();
    query.put("name", firstName);
    query.put("lastName", lastName);

    BasicDBObject push = new BasicDBObject();
    push.put("$push", new BasicDBObject("phone",phoneNumber));
    table.update(query, push);
}

{ "_id" : ObjectId("5297a5004a9ca519fad4e94d"), "lastName" : "Smith", "name" : "John", "phone" : [  "555 123 23 23"
,  "555 666 66 66 23" ] }
{ "_id" : ObjectId("5297a5004a9ca519fad4e94e"), "lastName" : "Doe", "name" : "Jane", "phone" : [  "555 123 44 44" ]
 }
{ "_id" : ObjectId("5297a5004a9ca519fad4e94f"), "name" : "John", "lastName" : "Smith" }