Mongodb-基于特定属性合并嵌套子文档数组_Mongodb_Aggregation Framework

Mongodb-基于特定属性合并嵌套子文档数组

mongodb

Mongodb-基于特定属性合并嵌套子文档数组,mongodb,aggregation-framework,Mongodb,Aggregation Framework,我构建了一个聚合，返回以下数据： [ { "users": [ { _id: 1, name: "John", age: 31 }, { _id: 2, name: "Jane", age: 26

我构建了一个聚合，返回以下数据：

 [
      {
        "users": [
          {
            _id: 1,
            name: "John",
            age: 31
          },
          {
            _id: 2,
            name: "Jane",
            age: 26
          }
        ],
        "teams": [
          {
            id: 1,
            name: "Team 1",
            color: "yellow"
          },
          {
            id: 2,
            name: "Team 2",
            color: "red"
          }
        ],
        "moreTeams": [
          {
            id: 1,
            name: "Team 1 - More",
          },
          {
            id: 2,
            name: "Team 2 - More",
          },
          {
            id: 3,
            name: "Team 3 - More",
            extra: "extra"
          }
        ]
      }
    ]

如何将“teams”和

moreTeams

分组到同一个数组中（基于id），保留所有属性并最终覆盖它们具有相同名称的位置

以下是我想要的结果：

 [
          {
            "users": [
              {
                _id: 1,
                name: "John",
                age: 31
              },
              {
                _id: 2,
                name: "Jane",
                age: 26
              }
            ],
            "groupedTeams": [
              {
                id: 1,
                name: "Team 1 - More",
                color: "yellow"
              },
              {
                id: 2,
                name: "Team 2 - More",
                color: "red"
              },
              {
                id: 3,
                name: "Team 3 - More",
                extra: "extra"
              }
            ]
          }
        ]

我尝试过使用$unwind和$group，但没有成功：(

Palyground示例：

```
$map
```
迭代
```
moreTeams
```
数组的循环
```
$filter
```
迭代
```
团队的循环
```
数组，并通过
```
id
```
```
$arrayElemAt
```
从上述过滤器获取第一个元素对象
```
$mergeObjects
```
将上面的对象从
```
arrayElemAt
```
和当前对象合并

现在我们在

teams

中合并了

moreTeams

，但我们也必须在

moreTeams

中合并

teams

$project

，

$filter

迭代

团队的循环

数组，如果

id

不在

moreTeams

```
$concatarray
```
到concat
```
moreTeams
```
及以上不在
```
moreTeams
```

db.collection.aggregate([
  {
    $addFields: {
      moreTeams: {
        $map: {
          input: "$moreTeams",
          as: "m",
          in: {
            $mergeObjects: [
              {
                $arrayElemAt: [
                  {
                    $filter: {
                      input: "$teams",
                      cond: { $eq: ["$$m.id", "$$this.id"] }
                    }
                  },
                  0
                ]
              },
              "$$m"
            ]
          }
        }
      }
    }
  },

  {
    $project: {
      users: 1,
      moreTeams: {
        $concatArrays: [
          "$moreTeams",
          {
            $filter: {
              input: "$teams",
              cond: { $not: { $in: ["$$this.id", "$moreTeams.id"] } }
            }
          }
        ]
      }
    }
  }
])