Ms access 连接两个表并显示不同的记录
我在MS Access 2010中有两个表： 零件注销表：Ms access 连接两个表并显示不同的记录,ms-access,join,Ms Access,Join,我在MS Access 2010中有两个表： 零件注销表： PART_ID DRAWN_DATE LOCATION_ID C0001 07/29/2013 501 C0002 07/29/2013 604 C0003 08/01/2013 703 C0004 08/01/2013 807 C0005 08/02/2013 505 C0006 08/02/2013 602 C0007 08/02/2013 707
PART_ID DRAWN_DATE LOCATION_ID
C0001 07/29/2013 501
C0002 07/29/2013 604
C0003 08/01/2013 703
C0004 08/01/2013 807
C0005 08/02/2013 505
C0006 08/02/2013 602
C0007 08/02/2013 707
C0008 08/03/2013 802
C0009 08/03/2013 803
C0001 10/01/2013 605
C0002 10/02/2013 704
C0004 10/05/2013 806
PART_ID RETURN_DATE LOCATION_ID
C0001 09/04/2013 STORE
C0002 09/05/2013 STORE
C0004 09/10/2013 STORE
C0007 09/12/2013 STORE
C0008 09/13/2013 STORE
C0002 10/03/2013 STORE
PART_ID DRAWN_DATE LOG-OUT LOCATION RETURN_DATE RETURN LOCATION
C0001 07/29/2013 501 09/04/2013 STORE
C0001 10/01/2013 605
C0002 07/29/2013 604 09/05/2013 STORE
C0002 10/02/2013 704 10/03/2013 STORE
C0003 08/01/2013 703
C0004 08/01/2013 807 09/10/2013 STORE
C0004 10/05/2013 806
C0005 08/02/2013 505
C0006 08/02/2013 602
C0007 08/02/2013 707 09/13/2013 STORE
C0008 08/03/2013 802 10/03/2013 STORE
C0009 08/03/2013 803
PART_ID DRAWN_DATE LOG-OUT LOCATION RETURN_DATE RETURN LOCATION
C0001 07/29/2013 501 09/04/2013 STORE
C0001 10/01/2013 605 `09/04/2013 STORE`
C0002 07/29/2013 604 09/05/2013 STORE
`C0002 07/29/2013 604` 10/03/2013 STORE
C0002 10/02/2013 704 `09/05/2013 STORE`
`C0002 10/02/2013 704 10/03/2013 STORE`
C0003 08/01/2013 703
C0004 08/01/2013 807 09/10/2013 STORE
C0004 10/05/2013 806 `09/10/2013 STORE`
C0005 08/02/2013 505
C0006 08/02/2013 602
C0007 08/02/2013 707 09/13/2013 STORE
C0008 08/03/2013 802 10/03/2013 STORE
C0009 08/03/2013 803
PART LOG-OUT TABLE -> PART RETURN TABLE
C0001 07/29/2013 501 -> C0001 09/04/2013 STORE
C0001 10/01/2013 605 -> C0001 09/04/2013 STORE
您需要加入另一个标准，或者您需要加入一些更独特的标识符，以实现您想要的结果。您的要求有点模糊，因此我可能会退出，但您似乎只想将返回时间与返回时间之前的时间配对，类似这样的情况
SELECT L.PART_ID, L.DRAWN_DATE, L.LOCATION_ID AS [LOG-OUT LOCATION], R.RETURN_DATE, R.LOCATION_ID AS RETURN_LOCATION FROM (SELECT * FROM [PART LOG-OUT] ORDER BY PART_ID) AS L LEFT OUTER JOIN (SELECT * FROM [PART RETURN] ORDER BY PART_ID) AS R ON L.PART_ID = R.PART_ID ORDER BY L.PART_ID, L.DRAWN_DATE, R.RETURN_DATE;
SELECT L.PART_ID, L.DRAWN_DATE, L.LOCATION_ID AS [LOG-OUT LOCATION],
MIN(R.RETURN_DATE), MIN(R.LOCATION_ID) AS RETURN_LOCATION
FROM (SELECT * FROM [LOG_OUT LOCATION]) AS L
LEFT JOIN (SELECT * FROM [PART_RETURN]) AS R
ON L.PART_ID = R.PART_ID AND L.DRAWN_DATE < R.RETURN_DATE
GROUP BY L.LOCATION_ID,L.PART_ID,L.DRAWN_DATE
ORDER BY L.PART_ID, L.DRAWN_DATE, MIN(R.RETURN_DATE)
请注意，由于您的问题中没有将单次购买与单次退货进行配对，也没有此类样本，因此，将它们配对的逻辑非常基本。在程序运行后，左外部联接将转换为左联接。如果应联接C0001,07/29/2013501，而不应联接C0001,10/01/2013605，你需要找到一种方法来区分两者。根据您展示的表结构，我看不到实现它的方法，因为无法知道您应该在零件返回表中加入哪个C0001。是的，这就是我要寻找的。谢谢！经过一些修改后，选择L.PART_ID、L.Drawed_DATE、L.LOCATION_ID作为[注销位置]、MINR.RETURN_DATE、MINR.LOCATION_ID作为从[PART LOG-OUT]中选择*作为L LEFT JOIN从[PART RETURN]中选择*作为L.PART_ID上的R=R.PART_ID和L.Drawed_DATE