Msmq 元素不是类型的实例

Msmq 元素不是类型的实例,msmq,linq-to-xsd,Msmq,Linq To Xsd,我使用Linq到XSD通过MSMQ发送数据。这是我的发送代码 public void Send() { string criMessageQueuePath = ConfigurationManager.AppSettings["CRIMessageQueuePath"]; if (!MessageQueue.Exists(criMessageQueuePath)) { Me

我使用Linq到XSD通过MSMQ发送数据。这是我的发送代码

public void Send()
        {
            string criMessageQueuePath = ConfigurationManager.AppSettings["CRIMessageQueuePath"];

            if (!MessageQueue.Exists(criMessageQueuePath))
            {
                MessageQueue.Create(criMessageQueuePath, false);
            }

            var messageQueue = new MessageQueue(criMessageQueuePath) { Label = "CRI Message Queue" };
            messageQueue.Formatter = new XmlMessageFormatter(new[] { typeof(XML) });

            var transaction = new MessageQueueTransaction();

            transaction.Begin();

            messageQueue.Send(CreateAuction(1), transaction);
            messageQueue.Send(CreateAuction(2), transaction);
            messageQueue.Send(CreateAuction(3), transaction);
            messageQueue.Send(CreateAuction(4), transaction);
            messageQueue.Send(CreateAuction(5), transaction);

            transaction.Commit();
        }

        private XML CreateAuction(int id)
        {
            var message = new XML {id = id};
            return message;
        }
这是我的接收代码

public IEnumerable<string> Receive()
        {
            string criMessageQueuePath = ConfigurationManager.AppSettings["CRIMessageQueuePath"];

        var messageQueue = new MessageQueue(criMessageQueuePath);

        Message[] messages = messageQueue.GetAllMessages();

        foreach (Message message in messages)
        {
            message.Formatter = new XmlMessageFormatter(new[] { typeof(XML) });
            yield return message.Body.ToString();
        }

        messageQueue.Purge();
    }
它失败的行是
var-typedXML=XML.Parse(XML)。错误是

Element is not an instance of type Domain.XML
对象的XSD是

<?xml version="1.0" encoding="Windows-1252"?>
<xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema" targetNamespace="Domain">
  <xs:element name="XML">
    <xs:complexType>
      <xs:sequence>
        <xs:element name="id" type="xs:int" />
      </xs:sequence>
    </xs:complexType>
  </xs:element>
</xs:schema>
我可以看到它产生了这个

"<XML>\r\n  <XML xmlns=\"Domain\">\r\n    <id>1</id>\r\n  </XML>\r\n</XML>"
“\r\n\r\n 1\r\n\r\n”

换句话说,它围绕整个xml生成一个额外的xml节点。如果我在调试器中删除这个额外的节点,那么一切都会正常工作。我做错了什么?

这是使用hte XmlMessageFormatter序列化对象并将其包装为XML的结果。我建议您将XML文档直接写入BodyStream属性

var msg = new Message();
var writer = new StreamWriter(msg.BodyStream);

writer.Write(xmlDoc.ToString());
writer.Flush();

queue.Send(msg);

这样,您就可以完全控制队列中发送的内容。格式化程序主要用于遗留用途,在将XML文档作为消息发送时不应使用。

这是使用hte XmlMessageFormatter序列化对象并将其包装为XML的结果。我建议您将XML文档直接写入BodyStream属性

var msg = new Message();
var writer = new StreamWriter(msg.BodyStream);

writer.Write(xmlDoc.ToString());
writer.Flush();

queue.Send(msg);
这样,您就可以完全控制队列中发送的内容。格式化程序主要用于遗留用途,在将XML文档作为消息发送时不应使用

var msg = new Message();
var writer = new StreamWriter(msg.BodyStream);

writer.Write(xmlDoc.ToString());
writer.Flush();

queue.Send(msg);