Dataweave:获取com.mulesoft.weave.model.structure.QualifiedName而不是字符串

我有一个数据库查询，返回如下数据：

"LABEL","CONTAINER_ID","STATUS"
"14.JW24","1006063116","F"
"14.JW25","1006063116","F"
"1.JW2M","9999997","R"
"8.282","9999999","R"
"4.135","9999999","F"
"6.43","9999999","F"
"11.12","9999999","R"
"14.JW12","1006063073","R"
"14.JW13","1006063073","R"
"14.JW10","1006063068","F"

%dw 1.0
%output application/java
---
payload filter $.STATUS == "F" groupBy $.CONTAINER_ID pluck $$ as :string

我正在使用Dataweave创建一个状态为“F”的不同容器id值的列表。比如：

["1006063116", "9999999", "1006063068"]

以下是我的dataweave脚本：

%dw 1.0
%output application/java
---
payload filter $.STATUS == "F" groupBy $.CONTAINER_ID pluck $$

这很好，只是我得到了com.mulesoft.weave.model.structure.QualifiedName对象列表，而不是字符串列表

---

如何修改dataweave脚本以获取字符串，或者如何从QualifiedName对象获取字符串值？我已尝试对对象调用toString（）和getName（）。前者不提供我需要的值，后者不起作用。

只需将结果元素转换为如下字符串：

"LABEL","CONTAINER_ID","STATUS"
"14.JW24","1006063116","F"
"14.JW25","1006063116","F"
"1.JW2M","9999997","R"
"8.282","9999999","R"
"4.135","9999999","F"
"6.43","9999999","F"
"11.12","9999999","R"
"14.JW12","1006063073","R"
"14.JW13","1006063073","R"
"14.JW10","1006063068","F"

%dw 1.0
%output application/java
---
payload filter $.STATUS == "F" groupBy $.CONTAINER_ID pluck $$ as :string

重要的部分是

as:string

替代解决方案：您可以使用

distinctBy

关键字获得类似的结果，并摆脱groupBy+pulk：

%dw 1.0
%output application/java
---
(payload filter $.status == "F").container_id distinctBy $

---

只需将结果元素强制转换为字符串，如下所示：

"LABEL","CONTAINER_ID","STATUS"
"14.JW24","1006063116","F"
"14.JW25","1006063116","F"
"1.JW2M","9999997","R"
"8.282","9999999","R"
"4.135","9999999","F"
"6.43","9999999","F"
"11.12","9999999","R"
"14.JW12","1006063073","R"
"14.JW13","1006063073","R"
"14.JW10","1006063068","F"

%dw 1.0
%output application/java
---
payload filter $.STATUS == "F" groupBy $.CONTAINER_ID pluck $$ as :string

重要的部分是

as:string

替代解决方案：您可以使用

distinctBy

关键字获得类似的结果，并摆脱groupBy+pulk：

%dw 1.0
%output application/java
---
(payload filter $.status == "F").container_id distinctBy $

---

谢谢我曾想过添加as:string，但出于某种原因，我认为需要先将表达式包装在parens中，这导致语法无效。谢谢！我曾想过添加as:string，但出于某种原因，我认为需要首先将表达式包装在parens中，这导致语法无效。