Mysql 如何在SQL中使用NOT？

这是我的关系模式，我正试图返回参与游戏但尚未获胜的参与者的名单

所以，我有

收集了所有的名字， 已从所有名称中删除获奖者，但不存在 删除所有绘图名称 但我无法排除那些没有参与游戏但仍在参与者表名称栏中的人

我的这部分代码不起作用

Game(p1, p2, pointsp1, pointsp2, ),
Participant(name, club, age)

FK Game(p1) references Participant(name),
FK Game(p2) references participant(name)

这是我的完整代码：

{ 
SELECT name 
FROM Participant 
JOIN Game 
WHERE Participant.name!=Game.p1 
    OR Participant.name!=Game.p2
}

---

假设您只需要玩过游戏但没有赢过的参与者列表，请尝试此项

SELECT name 
FROM Participant P
WHERE name NOT IN (
    SELECT DISTINCT p1
    FROM   Game G
    WHERE  pointsp1 > pointsp2
    UNION ALL
    SELECT DISTINCT p2
    FROM   Game G
    WHERE  pointsp1 < pointsp2
    UNION ALL
    SELECT ender
    FROM   Game G
    WHERE  pointsp1 = pointsp2
    UNION ALL
    SELECT starter
    FROM   Game G
    WHERE  pointsp1 = pointsp2   
    UNION 
    SELECT name 
    FROM   Participant 
    JOIN   Game 
    WHERE  Participant.name!=Game.p1 
        OR Participant.name!=Game.p2
)

---

第一个子选择获得所有优胜者，忽略平局，第二个子选择获得所有比赛的所有参与者。这不是完成任务的好方法，但它会起作用。

您可以使用下面的方法

select name
from participant
where name not in (
    select case 
      when g.pointsp1 < g.pointsp2 then p2
      when g.pointsp1 > g.pointsp2 then p1
      end as winner
    from game g
    where g.pointsp1 != g.pointsp2
)
  and name in (
    select p1 from game
    union all
    select p2 from game
)

可能重复的

SELECT name 
FROM Participant P
WHERE name NOT IN (
    SELECT DISTINCT p1
    FROM   Game G
    WHERE  pointsp1 > pointsp2
    UNION ALL
    SELECT DISTINCT p2
    FROM   Game G
    WHERE  pointsp1 < pointsp2
    UNION ALL
    SELECT ender
    FROM   Game G
    WHERE  pointsp1 = pointsp2
    UNION ALL
    SELECT starter
    FROM   Game G
    WHERE  pointsp1 = pointsp2)
OR  name not in (
    select p1 from game
    union all
    select p2 from game
)