MySQL：将VARCHAR转换为十进制并在范围之间查找

我在一列中有一些类似的数据

H1.1
H1.2
H1.3
H1.10
H50.1
H50.5
H55.5

我想在1.10到50.1之间搜索。我尝试过这样的查询，但没有得到想要的结果

SELECT p_code FROM table 
WHERE CONVERT(SUBSTRING_INDEX(REPLACE(`code`,'H',''), '.', 1),SIGNED INTEGER) between CONVERT(SUBSTRING_INDEX('1.1', '.', 1),SIGNED INTEGER) 
AND CONVERT(SUBSTRING_INDEX('1.99', '.', 1),SIGNED INTEGER) 
AND CONVERT(SUBSTRING_INDEX(REPLACE(`code`,'H',''), '.', 1),SIGNED INTEGER) 
between CONVERT(SUBSTRING_INDEX('1.1', '.', -1),SIGNED INTEGER) 
AND CONVERT(SUBSTRING_INDEX('1.99', '.', -1),SIGNED INTEGER) 
AND CONVERT(SUBSTRING_INDEX(REPLACE(`code`,'H',''), '.', 1),SIGNED INTEGER)>=CONVERT(SUBSTRING_INDEX('1.1', '.', 1),SIGNED INTEGER) 
AND CONVERT(SUBSTRING_INDEX(REPLACE(`code`,'H',''), '.', 1),SIGNED INTEGER)<=CONVERT(SUBSTRING_INDEX('1.99', '.', 1),SIGNED INTEGER)
AND CONVERT(SUBSTRING_INDEX(REPLACE(`code`,'H',''), '.', -1),SIGNED INTEGER)>=CONVERT(SUBSTRING_INDEX('1.1', '.', -1),SIGNED INTEGER) 
AND CONVERT(SUBSTRING_INDEX(REPLACE(`code`,'H',''), '.', -1),SIGNED INTEGER)<=CONVERT(SUBSTRING_INDEX('1.99', '.', -1),SIGNED INTEGER)
ORDER BY LENGTH(`code`)  desc ,`code` desc

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可以使用临时表执行此操作：

CREATE TEMPORARY TABLE temp_table (
    code decimal(5,3)
);

INSERT INTO temp_table (code)
SELECT CONVERT(REPLACE(`code`,'H',''), DECIMAL(5,3))
FROM `table`;
SELECT code FROM temp_table WHERE code BETWEEN 1.10 AND 50.1;

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嘿，谢谢你的回答…让我检查一下它是否工作创建临时表临时表代码小数5,3；在临时表代码中插入，从表中选择CONVERTREPLACEcode、'H'，小数5,3；从temp_表中选择代码，其中代码介于1.1和1.10之间；仅显示1.10，但结果必须为1.1,1.2,1.3是否为1.10和50.1之间的1.3？还是不？

CREATE TEMPORARY TABLE temp_table (
    code decimal(5,3)
);

INSERT INTO temp_table (code)
SELECT CONVERT(REPLACE(`code`,'H',''), DECIMAL(5,3))
FROM `table`;
SELECT code FROM temp_table WHERE code BETWEEN 1.10 AND 50.1;