MySQL在另一个表中按投票排序

我有这样的桌子：

entries:

ID      TITLE
1       Xyhargka
2       Hypothermia
3       Scale

及

VOTE1和VOTE2具有条目的ID。VOTE1代表2票，VOTE2代表1票

我正在尝试构造一个返回以下内容的查询：

ID      TITLE           VOTES
1       Xyhargka        3
3       Scale           2
2       Hypothermia     1

我一直在看JOIN语句，但我似乎不明白。。。我知道这不是有效的MySQL，但下面是我想要的伪代码：

SELECT v1 + v2 as votes, entries.* FROM entries
    JOIN (SELECT count(vote1) * 2 as v1 FROM votes WHERE vote1 = entries.id)
    JOIN (SELECT count(vote2) * 1 as v2 FROM votes WHERE vote2 = entries.id)
ORDER BY votes

---

这就是我在SQLSERVER中的实现方式，不确定MySQL中是否存在差异

SELECT V.ID,
  SUM( V.COUNT) AS TOTALCOUNT
FROM  (SELECT E1.ID AS ID, 2 AS COUNT
FROM VOTES AS V
JOIN ENTRIES AS E1
  ON V.VOTE1 = E1.ID
UNION ALL
SELECT E2.ID AS ID, 1 AS COUNT
FROM VOTES AS V
JOIN ENTRIES AS E2
  ON V.VOTE2 = E2.ID) AS V
GROUP BY V.ID
ORDER BY TOTALCOUNT DESC

---

您期望的结果与您的输入和对投票含义的描述完全不符。请更正示例或更好地解释您的意图。@JimGarrison已更新。。。如果伪代码看起来是错误的，我肯定是的。这是经过测试的吗？它看起来不错，而且运行正常，但没有返回预期结果..我需要更多信息来帮助您..；）没有关系！这是我的问题。非常好用，谢谢！

SELECT V.ID,
  SUM( V.COUNT) AS TOTALCOUNT
FROM  (SELECT E1.ID AS ID, 2 AS COUNT
FROM VOTES AS V
JOIN ENTRIES AS E1
  ON V.VOTE1 = E1.ID
UNION ALL
SELECT E2.ID AS ID, 1 AS COUNT
FROM VOTES AS V
JOIN ENTRIES AS E2
  ON V.VOTE2 = E2.ID) AS V
GROUP BY V.ID
ORDER BY TOTALCOUNT DESC