mysql中的交叉表
我有这些数据mysql中的交叉表,mysql,crosstab,Mysql,Crosstab,我有这些数据 | car_name | year | price | Honda | 2011 | 123 | Honda | 2012 | 124 | Suzuki | 2011 | 1234 | Suzuki | 2012 | 1235 我要怎么把它变成 | car_name | 2011 | 2012 | | Honda | 123 | 124 | Suzuki | 1234 | 1235 请用PHP帮助我,以下是您的答案: $sql = "S
| car_name | year | price
| Honda | 2011 | 123
| Honda | 2012 | 124
| Suzuki | 2011 | 1234
| Suzuki | 2012 | 1235
我要怎么把它变成
| car_name | 2011 | 2012 |
| Honda | 123 | 124
| Suzuki | 1234 | 1235
请用PHP帮助我,以下是您的答案:
$sql = "SELECT DISTINCT `year` FROM `table`";
$result = mysql_query($sql);
$sql2_select = "SELECT t1.`car_name`";
$sql2_from = "FROM `table` t1";
$i = 2;
while($row = mysql_fetch_row($result)) {
$year = $row[0];
$sql2_select .= ", t{$i}.`price` AS `$year`"
$sql_from .= " LEFT JOIN (SELECT `car_name`, `price` WHERE `year` = '$year') AS t{$i}";
$sql_from .= " ON t1.`car_name` = t2.`car_name`";
$i++;
}
$sql2 = $sql2_select . ' ' . $sql2_from . ' ' . "GROUP BY t1.car_name";
$result = mysql_query($sql2);
在MySQL中,您可以执行以下操作:
SELECT car_name,
max(case when year = '2011' then price ELSE 0 END) as `2011`,
max(case when year = '2012' then price ELSE 0 END) as `2012`
FROM t
GROUP BY car_name
请参见在MySQL中执行交叉表的一种方法是使用子选择:
select car_name,
(select price from t t2 where t2.car_name = t1.car_name and year = 2011) as '2011',
(select price from t t2 where t2.car_name = t1.car_name and year = 2012) as '2012'
from t t1
group by car_name
如果你每年每辆车有一个以上的记录,那么sum(price)。你可以使用PHP或其他语言来创建查询,还是所有的查询都必须在MySQL中完成?事实上,我需要所有的查询都必须在MySQL更简洁的版本中完成:“选择车名,max(If(year='2011',price,0))作为
2011
,max(If(year='2012',price,0))作为2012年的t集团的