Mysql 时间戳差异,仅获取小时、分钟和秒
所以我每行有两张表,我用它来计算平均时间,单位是分钟Mysql 时间戳差异,仅获取小时、分钟和秒,mysql,time,diff,Mysql,Time,Diff,所以我每行有两张表,我用它来计算平均时间,单位是分钟 SELECT Sec_to_time (Avg (Timestampdiff (second, `survival`, `lastupdate`))) FROM main 但是我想单独获得小时、分钟和秒,这样我就可以在php中回显它们。您可以使用MySQL函数将从秒到秒时间返回的时间分解为其组件 为避免重复计算,您可以将计算包装起来: SELECT HOUR(x.timeDiff), MINUTE(x.timeDiff), SECOND
SELECT Sec_to_time (Avg (Timestampdiff (second, `survival`, `lastupdate`)))
FROM main
但是我想单独获得小时、分钟和秒,这样我就可以在php中回显它们。您可以使用MySQL函数将从秒到秒时间返回的时间分解为其组件
为避免重复计算,您可以将计算包装起来:
SELECT HOUR(x.timeDiff), MINUTE(x.timeDiff), SECOND(x.timeDiff)
FROM
(
SELECT Sec_to_time(Avg (Timestampdiff (second, `survival`, `lastupdate`))) as timeDiff
FROM main
) AS x
您可以使用MySQL函数将从秒到秒时间返回的时间分解为其组件
为避免重复计算,您可以将计算包装起来:
SELECT HOUR(x.timeDiff), MINUTE(x.timeDiff), SECOND(x.timeDiff)
FROM
(
SELECT Sec_to_time(Avg (Timestampdiff (second, `survival`, `lastupdate`))) as timeDiff
FROM main
) AS x
MySql中有hour()、minute()和second()函数
MySql中有hour()、minute()和second()函数
试试:
select concat(HOUR(Sec_to_time(Avg (Timestampdiff (second, login_datetime, logout_datetime)))),
'hr ',
MINUTE(Sec_to_time(Avg (Timestampdiff (second, login_datetime, logout_datetime)))),
'min ',
SECOND(Sec_to_time(Avg (Timestampdiff (second, login_datetime, logout_datetime)))),
'sec ')
as his_time from table_name;
尝试:
谢谢,这很好用。但我该如何回应每一个小时、每一分钟和每一秒呢?谢谢,这很好。但我该如何回应每一小时、每一分钟和每一秒?