if语句的mysql语法问题
我对if语句附近的这个语法有问题,我一直在 检查附近的mysql语法if语句的mysql语法问题,mysql,phpmyadmin,syntax-error,Mysql,Phpmyadmin,Syntax Error,我对if语句附近的这个语法有问题,我一直在 检查附近的mysql语法 == 'purp1' and product_price==53, 13, 0) as ShipWeight 这就是我正在努力实现的目标。有什么想法吗 select wp_cart66_order_items.order_id as Order_ID, wp_cart66_orders.trans_id as Order_Number, wp_cart66_orders.bill_first_name as
== 'purp1' and product_price==53, 13, 0) as ShipWeight
这就是我正在努力实现的目标。有什么想法吗
select wp_cart66_order_items.order_id as Order_ID,
wp_cart66_orders.trans_id as Order_Number,
wp_cart66_orders.bill_first_name as Bill_First_Name,
wp_cart66_orders.bill_last_name as Bill_Last_Name,
wp_cart66_orders.ship_first_name as Ship_First_Name,
wp_cart66_orders.ship_last_name as Ship_Last_Name,
wp_cart66_orders.ship_address as Ship_Address1,
wp_cart66_orders.ship_address2 as Ship_Address2,
wp_cart66_orders.ship_city as Ship_City,
wp_cart66_orders.ship_state as Ship_State,
wp_cart66_orders.ship_zip as Ship_zip,
wp_cart66_order_items.item_number as Item_Number,
wp_cart66_order_items.product_price as Price,
wp_cart66_order_items.Description as OrderItemsDescription,
if(item_number == 'purp1' and product_price==53, 13, 0) as ShipWeight
from wp_cart66_orders
inner join wp_cart66_order_items
on wp_cart66_orders.id=wp_cart66_order_items.order_id
where wp_cart66_orders.ordered_on between "2013-04-01 00:00:00" and "2013-04-02 23:59:59"
在浏览文档时,我找不到mysql是否支持
=
,请尝试将其更改为=
if(item_number = 'purp1' and product_price=53, 13, 0) as ShipWeight
CASE()
删除double==非常好,但是我现在遇到了另一个问题,当我添加另一行时,我得到了两个Shipweight列,如何添加多行而不得到所有这些列?'if(item_number='marley1'和product_price='12.00',2,0)作为Shipweight,if(item_number='samp1'和product_price='19.50',4,0)作为ShipWeight'你的意思是结合这两个?如果我有多个产品具有相同的价格,我如何将它们添加到一行,这样我就不会有一个巨大的脚本?我要用逗号把它们分开吗?”当项目编号为“hell1,cav1,marley1”且产品价格为“15.00”时,则2“太好了,非常感谢,非常感谢!!
CASE
WHEN item_number = 'marley1' and product_price='12.00' THEN 2
WHEN item_number = 'samp1' and product_price='19.50' THEN 4
ELSE 0
END ShipWeight